bash + for 循环 + 输出索引号和元素
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bash + for loop + output index number and element
提问by HattrickNZ
This is my array:
这是我的数组：
$ ARRAY=(one two three)
How do I print the array so I have the output like: index i, element[i]using the printfor forloop I use below
如何打印数组，以便得到如下输出：index i, element[i]使用我在下面使用的printforfor循环
1,one
2,two
3,three
Some notes for my reference
一些笔记供我参考
1 way to print the array:
1种打印数组的方法：
$ printf "%s\n" "${ARRAY[*]}"
one two three
2 way to print the array
2 打印数组的方法
$ printf "%s\n" "${ARRAY[@]}"
one
two
three
3 way to print the array
打印数组的3种方式
$ for elem in "${ARRAY[@]}"; do echo "$elem"; done
one
two
three
4 way to print the array
4种方式打印数组
$ for elem in "${ARRAY[*]}"; do echo "$elem"; done
one two three
A nothe way to look at the array
查看数组的另一种方式
$ declare -p ARRAY
declare -a ARRAY='([0]="one" [1]="two" [2]="three")'
回答by xxfelixxx
You can iterate over the indices of the array, i.e. from 0to ${#array[@]} - 1.
您可以遍历数组的索引，即 from 0to ${#array[@]} - 1。
#!/usr/bin/bash
array=(one two three)
# ${#array[@]} is the number of elements in the array
for ((i = 0; i < ${#array[@]}; ++i)); do
# bash arrays are 0-indexed
position=$(( $i + 1 ))
echo "$position,${array[$i]}"
done
Output
输出
1,one
2,two
3,three
回答by LegZ
The simplest way to iterate seems to be:
最简单的迭代方法似乎是：
#!/usr/bin/bash
array=(one two three)
# ${!array[@]} is the list of all the indexes set in the array
for i in ${!array[@]}; do
echo "$i, ${array[$i]}"
done
