如何在Python中重复字符串中的单个字符
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How to repeat individual characters in strings in Python
提问by Jason S
I know that
我知道
"123abc" * 2
evaluates as "123abc123abc", but is there an easy way to repeat individual letters N times, e.g. convert "123abc"to "112233aabbcc"or "111222333aaabbbccc"?
评估为"123abc123abc"，但是有没有一种简单的方法可以将单个字母重复 N 次，例如转换"123abc"为"112233aabbcc"或"111222333aaabbbccc"？
回答by Bahrom
回答by alecxe
An alternative itertools-problem-overcomplicating-style option with repeat(), izip()and chain():
itertools使用repeat(),izip()和的替代-problem-overcomplicating-style 选项chain()：
>>> from itertools import repeat, izip, chain
>>> "".join(chain(*izip(*repeat(s, 2))))
'112233aabbcc'
>>> "".join(chain(*izip(*repeat(s, 3))))
'111222333aaabbbccc'
Or, "I know regexes and I'll use it for everything"-style option:
或者，“我知道正则表达式，我会用它做所有事情”风格的选项：
>>> import re
>>> n = 2
>>> re.sub(".", lambda x: x.group() * n, s) # or re.sub('(.)', r'' * n, s) - thanks Eduardo
'112233aabbcc'
Of course, don't use these solutions in practice.
当然，不要在实践中使用这些解决方案。
回答by sarnthil
Or another way to do it would be using map:
或者另一种方法是使用map：
"".join(map(lambda x: x*7, "map"))
回答by Gerges
And since I use numpy for everything, here we go:
因为我对所有东西都使用 numpy，所以我们开始：
import numpy as np
n = 4
''.join(np.array(list(st*n)).reshape(n, -1).T.ravel())
回答by khappe khappe
here is my naive solution
这是我天真的解决方案
text = "123abc"
result = ''
for letters in text:
result += letters*3
print(result)
output: 111222333aaabbbccc
输出：111222333aaabbbccc
回答by Ano. Nymous
If you want to repeat individualletters you can just replace the letter with n letters e.g.
如果你想重复单个字母，你可以用 n 个字母替换字母，例如
>>> s = 'abcde'
>>> s.replace('b', 'b'*5, 1)
'abbbbbcde'
回答by julienc
@Bahrom's answer is probably clearer than mine, but just to say that there are many solutions to this problem:
@Bahrom 的答案可能比我的更清楚，但只是说这个问题有很多解决方案：
>>> s = '123abc'
>>> n = 3
>>> reduce(lambda s0, c: s0 + c*n, s, "")
'111222333aaabbbccc'
Note that reduceis not a built-in in python 3, and you have to use functools.reduceinstead.
请注意，这reduce不是 python 3 中的内置函数，您必须使用它functools.reduce。
回答by Eduardo Cuesta
Or using regular expressions:
或者使用正则表达式：
>>> import re
>>> s = '123abc'
>>> n = 3
>>> re.sub('(.)', r'' * n, s)
'111222333aaabbbccc'
回答by af3ld
Another way:
其它的办法：
def letter_repeater(n, string):
word = ''
for char in list(string):
word += char * n
print word
letter_repeater(4, 'monkeys')
mmmmoooonnnnkkkkeeeeyyyyssss
