如何循环遍历 JavaScript 对象的深层嵌套属性?

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时间:2020-10-25 16:18:53  来源:igfitidea点击:

How do I loop through deeply nested properties of a JavaScript object?

javascript

提问by timmackay

I have a JavaScript object with 3 levels of nesting. I am having a hard time getting the values from the 3rd level of nesting.

我有一个具有 3 级嵌套的 JavaScript 对象。我很难从第 3 级嵌套中获取值。

I have done some research on SO and get the basic looping but I can't seem to get past the first level.

我已经对 SO 进行了一些研究并获得了基本的循环,但我似乎无法通过第一级。

Here is my code

这是我的代码

var customers = {
   "cluster": [{
      "id": "cluster1.1",
      "color": "blue",
      "flights": "784",
      "profit": "524125",
      "clv": "2364",
      "segment": [{
         "id": "segment1.1",
         "color": "green",
         "flights": "82",
         "profit": "22150",
         "clv": "1564",
         "node": [{
            "id": "node1.1",
            "color": "orange",
            "xpos": "1",
            "ypos": "1"
         }, {
            "id": "node1.2",
            "color": "orange",
            "xpos": "1",
            "ypos": "2"
         }, {
            "id": "node1.3",
            "color": "orange",
            "xpos": "1",
            "ypos": "3"
         }, {
            "id": "node1.4",
            "color": "orange",
            "xpos": "1",
            "ypos": "4"
         }]
      }, {
         "id": "segment1.2",
         "color": "red",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node2.1",
            "color": "tan",
            "xpos": "2",
            "ypos": "1"
         }, {
            "id": "node2.2",
            "color": "tan",
            "xpos": "2",
            "ypos": "2"
         }, {
            "id": "node2.3",
            "color": "tan",
            "xpos": "2",
            "ypos": "3"
         }, {
            "id": "node2.4",
            "color": "tan",
            "xpos": "2",
            "ypos": "4"
         }]
      }]
   }, {
      "id": "cluster1.2",
      "flights": "4",
      "profit": "5245",
      "clv": "2364",
      "segment": [{
         "id": "segment1.2",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node3.1",
            "xpos": "3",
            "ypos": "1"
         }, {
            "id": "node3.2",
            "xpos": "3",
            "ypos": "2"
         }, {
            "id": "node3.3",
            "xpos": "3",
            "ypos": "3"
         }, {
            "id": "node3.4",
            "xpos": "3",
            "ypos": "4"
         }]
      }]
   }, {
      "id": "cluster1.3",
      "flights": "10",
      "profit": "456978",
      "clv": "548",
      "segment": [{
         "id": "segment1.3",
         "flights": "2",
         "profit": "2150",
         "clv": "1564",
         "node": [{
            "id": "node4.1",
            "xpos": "4",
            "ypos": "1"
         }, {
            "id": "node4.2",
            "xpos": "4",
            "ypos": "2"
         }, {
            "id": "node4.3",
            "xpos": "4",
            "ypos": "3"
         }, {
            "id": "node4.4",
            "xpos": "4",
            "ypos": "4"
         }]
      }]
   }]
};

How do I loop through and retrieve xpos and ypos from within node?

如何从节点内循环并检索 xpos 和 ypos?

回答by zzzzBov

You have an object (customers) with an array stored at cluster, which you can iterate through with

您有一个对象 ( customers) cluster,其中存储了一个数组,您可以使用它进行迭代

var i, cluster;
for (i = 0; i < customers.cluster.length; i++)
{
  cluster = customers.cluster[i];
}

clusterhas an array stored at segmentwhich you can iterate through with:

cluster存储了一个数组segment,您可以在其中迭代:

var j, segment;
for (j = 0; j < cluster.segment.length; j++)
{
  segment = cluster.segment[j];
}

segmenthas an array stored at nodewhich you can iterate through with:

segment存储了一个数组node,您可以在其中迭代:

var k, node;
for (k = 0; k < segment.node.length; k++)
{
  node = segment.node[k];
}

You can combine all of these to iterate through every node of every segment of every cluster on customers just by combining these loops:

您可以将所有这些组合起来,通过组合这些循环来遍历客户上每个集群的每个段的每个节点:

var i, cluster, j, segment, k, node;
for (i = 0; i < customers.cluster.length; i++)
{
  cluster = customers.cluster[i];

  for (j = 0; j < cluster.segment.length; j++)
  {
    segment = cluster.segment[j];

    for (k = 0; k < segment.node.length; k++)
    {
      node = segment.node[k];
      //access node.xpos, node.ypos here
    }
  }
}