SQL Server:如何测试字符串是否只有数字字符
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SQL Server : How to test if a string has only digit characters
提问by skyline01
I am working in SQL Server 2008. I am trying to test whether a string (varchar) has only digit characters (0-9). I know that the IS_NUMERIC function can give spurious results. (My data can possibly have $ signs, which should not pass the test.) So, I'm avoiding that function.
我在 SQL Server 2008 中工作。我试图测试字符串 (varchar) 是否只有数字字符 (0-9)。我知道 IS_NUMERIC 函数会给出虚假结果。(我的数据可能有 $ 符号,它不应该通过测试。)所以,我避免使用该功能。
I already have a test to see if a string has any non-digit characters, i.e.,
我已经有一个测试,看看一个字符串是否有任何非数字字符,即,
some_column LIKE '%[^0123456789]%'
I would think that the only-digits test would be something similar, but I'm drawing a blank. Any ideas?
我认为唯一数字测试会类似,但我正在画一个空白。有任何想法吗?
回答by P?????
Use Not Like
用 Not Like
where some_column NOT LIKE '%[^0-9]%'
Demo
演示
declare @str varchar(50)='50'--'asdarew345'
select 1 where @str NOT LIKE '%[^0-9]%'
回答by Bensonius
There is a system function called ISNUMERICfor SQL 2008 and up. An example:
对于 SQL 2008 及更高版本,有一个名为ISNUMERIC的系统函数。一个例子:
SELECT myCol
FROM mTable
WHERE ISNUMERIC(myCol)<> 1;
I did a couple of quick tests and also looked further into the docs:
我做了几个快速测试,并进一步查看了文档:
ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0.
ISNUMERIC returns 1 when the input expression evaluates to a valid numeric data type; otherwise it returns 0.
Which means it is fairly predictable for example
这意味着它是相当可预测的,例如
-9879210433
would pass but 987921-0433
does not.
$9879210433
would pass but 9879210$433
does not.
-9879210433
会通过,但987921-0433
不会。
$9879210433
会通过,但9879210$433
不会。
So using this information you can weed out based on the list of valid currency symbolsand +
& -
characters.
回答by Victor Barajas
Solution:
where some_column NOT LIKE '%[^0-9]%'
Is correct.
解决方法:
where some_column NOT LIKE '%[^0-9]%'
正确。
Just one important note: Add validation for when the string column = ''
(empty string). This scenario will return that ''
is a valid number as well.
只有一个重要的注意事项:当字符串 column = ''
(空字符串)时添加验证。这种情况也将返回''
一个有效数字。
回答by Dudi Konfino
DECLARE @x int=1
declare @exit bit=1
WHILE @x<=len('123c') AND @exit=1
BEGIN
IF ascii(SUBSTRING('123c',@x,1)) BETWEEN 48 AND 57
BEGIN
set @x=@x+1
END
ELSE
BEGIN
SET @exit=0
PRINT 'string is not all numeric -:('
END
END