C# 如何动态创建 Expression<Func<MyClass, bool>> 谓词?
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How do I dynamically create an Expression<Func<MyClass, bool>> predicate?
提问by Senkwe
How would I go about using an Expression Tree to dynamically create a predicate that looks something like...
我将如何使用表达式树来动态创建一个看起来像......
(p.Length== 5) && (p.SomeOtherProperty == "hello")
So that I can stick the predicate into a lambda expression like so...
这样我就可以像这样将谓词粘贴到 lambda 表达式中......
q.Where(myDynamicExpression)...
I just need to be pointed in the right direction.
我只需要指出正确的方向。
Update:Sorry folks, I left out the fact that I want the predicate to have multiple conditions as above. Sorry for the confusion.
更新:抱歉各位,我忽略了我希望谓词具有上述多个条件的事实。对困惑感到抱歉。
采纳答案by Marc Gravell
Original
原来的
Like so:
像这样:
var param = Expression.Parameter(typeof(string), "p");
var len = Expression.PropertyOrField(param, "Length");
var body = Expression.Equal(
len, Expression.Constant(5));
var lambda = Expression.Lambda<Func<string, bool>>(
body, param);
Updated
更新
re (p.Length== 5) && (p.SomeOtherProperty == "hello")
:
回复(p.Length== 5) && (p.SomeOtherProperty == "hello")
:
var param = Expression.Parameter(typeof(SomeType), "p");
var body = Expression.AndAlso(
Expression.Equal(
Expression.PropertyOrField(param, "Length"),
Expression.Constant(5)
),
Expression.Equal(
Expression.PropertyOrField(param, "SomeOtherProperty"),
Expression.Constant("hello")
));
var lambda = Expression.Lambda<Func<SomeType, bool>>(body, param);
回答by Daniel Earwicker
To combine several predicates with the &&
operator, you join them together two at a time.
要将多个谓词与&&
运算符组合在一起,您可以一次将两个谓词连接在一起。
So if you have a list of Expression objects called predicates
, do this:
因此,如果您有一个名为 的 Expression 对象列表predicates
,请执行以下操作:
Expression combined = predicates.Aggregate((l, r) => Expression.AndAlso(l, r));
回答by Schotime
Use the predicate builder.
使用谓词构建器。
http://www.albahari.com/nutshell/predicatebuilder.aspx
http://www.albahari.com/nutshell/predicatebuilder.aspx
Its pretty easy!
它很容易!
回答by Alan
To associate Lambda expression each other: An other way is to use the following code. It s more flexible than the Schotime answer in my advice and work perfectly. No external Nuggets needed
将 Lambda 表达式相互关联: 另一种方法是使用以下代码。它比我的建议中的 Schotime 答案更灵活并且工作完美。不需要外部掘金队
Framework 4.0
框架 4.0
// Usage first.Compose(second, Expression.And)
public static Expression<T> Compose<T>(this Expression<T> First, Expression<T> Second, Func<Expression, Expression, Expression> Merge)
{
// build parameter map (from parameters of second to parameters of first)
Dictionary<ParameterExpression,ParameterExpression> map = First.Parameters.Select((f, i) => new { f, s = Second.Parameters[i] }).ToDictionary(p => p.s, p => p.f);
// replace parameters in the second lambda expression with parameters from the first
Expression secondBody = ParameterRebinder.ReplaceParameters(map, Second.Body);
// apply composition of lambda expression bodies to parameters from the first expression
return Expression.Lambda<T>(Merge(First.Body, secondBody), First.Parameters);
}
public static Expression<Func<T, bool>> And<T>(this Expression<Func<T, bool>> First, Expression<Func<T, bool>> Second)
{
return First.Compose(Second, Expression.And);
}
public static Expression<Func<T, bool>> Or<T>(this Expression<Func<T, bool>> First, Expression<Func<T, bool>> second)
{
return First.Compose(second, Expression.Or);
}
public class ParameterRebinder : ExpressionVisitor
{
private readonly Dictionary<ParameterExpression, ParameterExpression> map;
public ParameterRebinder(Dictionary<ParameterExpression, ParameterExpression> map)
{
this.map = map ?? new Dictionary<ParameterExpression, ParameterExpression>();
}
public static Expression ReplaceParameters(Dictionary<ParameterExpression, ParameterExpression> map, Expression exp)
{
return new ParameterRebinder(map).Visit(exp);
}
protected override Expression VisitParameter(ParameterExpression p)
{
ParameterExpression replacement;
if (map.TryGetValue(p, out replacement))
{
p = replacement;
}
return base.VisitParameter(p);
}
}
回答by MurariAlex
I have a open-source project called Exprelsiorthat provides very simple ways to create dynamic predicates:
我有一个名为Exprelsior的开源项目,它提供了非常简单的方法来创建动态谓词:
Based on your example:
根据您的示例:
var exp1 = ExpressionBuilder.CreateBinary<YourClass>("MyProperty.Length", 5, ExpressionOperator.Equals);
var exp2 = ExpressionBuilder.CreateBinary<YourClass>("SomeOtherProperty", "hello", ExpressionOperator.Equals);
var fullExp = exp1.And(exp2);
// Use it normally...
q.Where(fullExp)
It even supports full text predicate generation, so you can receive any dynamic query from an HTTP GET method, for example:
它甚至支持全文谓词生成,因此您可以从 HTTP GET 方法接收任何动态查询,例如:
var exp1 = ExpressionBuilder.CreateBinaryFromQuery<YourClass>("eq('MyProperty.Length', '5')");
var exp2 = ExpressionBuilder.CreateBinaryFromQuery<YourClass>("eq('SomeOtherProperty', 'hello')");
var fullExp = exp1.And(exp2);
// Use it normally...
q.Where(fullExp)
It supports a lot more data types and operators.
它支持更多的数据类型和运算符。