wpf 如何在WPF中创建垂直菜单并在菜单右侧制作子菜单？
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How to create the vertical menu and make the submenu on the menu's right side in WPF?
提问by Prince
As the picture show, how can I create the menu like that in WPF?
如图所示，如何在 WPF 中创建这样的菜单？
I've tried that by using Popup control and Menus control, but the effect is not ideal
用Popup控件和Menus控件试过，效果不理想
回答by Liero
You have to do two things:
你必须做两件事：
Set Menu.ItemsPanel to StackPanel
Change the Popup's Placementof MenuItems from Bottom to Right. I just right-clicked on the MenuItem in visual studio designer and picked EditTempalate from context menu. In the template I found popup control and changed the placement to Right. It works nice
将 Menu.ItemsPanel 设置为 StackPanel
将弹出的菜单项的位置从底部更改为右侧。我只是在 Visual Studio 设计器中右键单击 MenuItem，然后从上下文菜单中选择 EditTempalate。在模板中，我找到了弹出控件并将位置更改为 Right。效果很好
Final xaml:
最终的xaml：
<Menu HorizontalAlignment="Left">
<Menu.ItemsPanel>
<ItemsPanelTemplate>
<StackPanel />
</ItemsPanelTemplate>
</Menu.ItemsPanel>
<MenuItem Header="Item 1" />
<MenuItem Header="Item 2" Style="{StaticResource MenuItemStyle1}">
<MenuItem Header="Sub item 1" />
<MenuItem Header="Sub item 2" />
<MenuItem Header="Sub item 3" />
<MenuItem Header="Sub item 4" />
</MenuItem>
<MenuItem Header="Item 3" />
<MenuItem Header="Item 4" />
</Menu>
And the result:
结果：
回答by Heena Patil
You can implement this menu using ToggleButton and Popup.
您可以使用 ToggleButton 和 Popup 来实现此菜单。
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="100"></ColumnDefinition>
<ColumnDefinition Width="500"></ColumnDefinition>
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition Height="30"></RowDefinition>
<RowDefinition Height="30"></RowDefinition>
<RowDefinition Height="*"></RowDefinition>
</Grid.RowDefinitions>
<ToggleButton Content="Home" Name="ToggleButton1" Foreground="Black" Focusable="false" IsChecked="{Binding Path=IsOpen,Mode=TwoWay,ElementName=Popup1}" ClickMode="Press"/>
<ToggleButton Content="Controls" Grid.Row="1" Name="ToggleButton2" Foreground="Black" Focusable="false" IsChecked="{Binding Path=IsOpen,Mode=TwoWay,ElementName=Popup2}" ClickMode="Press"/>
<Popup VerticalAlignment="Top" PlacementTarget="{Binding ElementName=ToggleButton1}" Grid.Column="1" HorizontalAlignment="Left" Name="Popup1" Placement="Right" IsOpen="False" AllowsTransparency="True" Focusable="False" PopupAnimation="Slide">
<Grid Background="Gray" HorizontalAlignment="Left" VerticalAlignment="Stretch" SnapsToDevicePixels="True" Width="300" Height="300">
<StackPanel HorizontalAlignment="Stretch" Background="Transparent">
<TextBlock Text="Xaml"></TextBlock>
<TextBlock Text="Routed Events"></TextBlock>
<TextBlock Text="Visual Tree"></TextBlock>
</StackPanel>
</Grid>
</Popup>
<Popup VerticalAlignment="Top" PlacementTarget="{Binding ElementName=ToggleButton2}" Grid.Column="1" HorizontalAlignment="Left" Name="Popup2" Placement="Right" IsOpen="False" AllowsTransparency="True" Focusable="False" PopupAnimation="Slide">
<Grid Background="Green" HorizontalAlignment="Left" VerticalAlignment="Stretch" SnapsToDevicePixels="True" Width="300" Height="300">
<StackPanel HorizontalAlignment="Stretch" Background="Transparent">
<TextBlock Text="Xaml"></TextBlock>
<TextBlock Text="Routed Events"></TextBlock>
<TextBlock Text="Visual Tree"></TextBlock>
</StackPanel>
</Grid>
</Popup>
</Grid>
Output
输出
回答by kulotskie
try to use MenuItem.ItemsPanel
尝试使用 MenuItem.ItemsPanel
for example
例如
<Menu>
<Menu.ItemsPanel>
<ItemsPanelTemplate>
<VirtualizingStackPanel Orientation="Vertical"/>
</ItemsPanelTemplate>
</Menu.ItemsPanel>
</Menu>
回答by SledgeHammer
Just use the PopupMenu control man. No need for changing the items panel.
只需使用 PopupMenu 控制人员即可。无需更改项目面板。
