java JsonMappingException: 意外令牌 (START_OBJECT)

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/31242819/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-11-02 18:19:43  来源:igfitidea点击:

JsonMappingException: Unexpected token (START_OBJECT)

javajsonHymanson

提问by gleX

I'm having problem with the user of Codehaus Hymanson. I have an object with the next attributes and mapper declaration:

我遇到了 Codehaus Hymanson 用户的问题。我有一个具有下一个属性和映射器声明的对象:

public class AuthenticatedPrincipal implements Serializable, Principal {
      @JsonIgnore
      private final static ObjectMapper mapper = new ObjectMapper().enable(DeserializationConfig.Feature.ACCEPT_SINGLE_VALUE_AS_ARRAY).enableDefaultTyping(ObjectMapper.DefaultTyping.NON_FINAL)
      .setSerializationInclusion(JsonSerialize.Inclusion.NON_NULL).setVisibility(JsonMethod.FIELD, JsonAutoDetect.Visibility.ANY);

  private String name;

  private Collection<String> roles;

  private Collection<String> groups;

  private boolean adminPrincipal;
...
  @JsonIgnore
  public String serialize() {
    try {
      return mapper.writeValueAsString(this);
    } catch (IOException e) {
      throw new RuntimeException("Unable to serialize Principal:" + toString(), e);
    }
  }

  @JsonIgnore
  public static AuthenticatedPrincipal deserialize(String json) {
    try {
      return mapper.readValue(json, AuthenticatedPrincipal.class);
    } catch (IOException e) {
      throw new RuntimeException("Unable to serialize Principal:" + json, e);
    }
  }
}

That is used from another class:

这是从另一个类使用的:

public class AuthRequest {

  @Transient
  private AuthenticatedPrincipal principal;
  @PreUpdate
  @PrePersist
  public void encodePrincipal() {
    if (principal != null) {
        this.encodedPrincipal = principal.serialize();
    }
  }

  @PostLoad
  @PostPersist
  @PostUpdate
  public void decodePrincipal() {
    if (StringUtils.isNotBlank(encodedPrincipal)) {
        this.principal = AuthenticatedPrincipal.deserialize(encodedPrincipal);
    }
  }
}

When I execute the funtionality that generate a String like this:

当我执行生成这样的字符串的功能时:

Principal:{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}

When the method AuthenticatedPrincipal.deserialize(encodedPrincipal); is called parsing a Json parameter but that method fail with this error:

当方法 AuthenticatedPrincipal.deserialize(encodedPrincipal); 被称为解析 Json 参数,但该方法因以下错误而失败:

org.codehaus.Hymanson.map.JsonMappingException: Unexpected token (START_OBJECT), expected START_ARRAY: need JSON Array to contain As.WRAPPER_ARRAY type information for class com.trent.app.lib.principal.AuthenticatedPrincipal
 at [Source: java.io.StringReader@40fa255; line: 1, column: 1]

Can anyone help me?

谁能帮我?

回答by Simon

Principal:{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}

Is not valid JSON. It needs to look like this

不是有效的 JSON。它需要看起来像这样

{"adminPrincipal":false,"displayName":"sdfas","groupAware":false,"name":"sdfas"}

(without the Principal:at the start)

(没有Principal:开头)