php 转换为日期格式 dd/mm/yyyy
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Convert to date format dd/mm/yyyy
提问by Rui Gon?alves
I have the following date: 2010-04-19 18:31:27. I would like to convert this date to the dd/mm/yyyyformat.
我有以下日期：2010-04-19 18:31:27。我想将此日期转换为dd/mm/yyyy格式。
回答by Michael Mrozek
You can use a regular expression or some manual string fiddling, but I think I prefer:
您可以使用正则表达式或一些手动字符串摆弄，但我想我更喜欢：
date("d/m/Y", strtotime($str));
回答by Murali Krishna kilari
<?php
$test1='2010-04-19 18:31:27';
echo date('d/m/Y',strtotime($test1));
?>
try this
尝试这个
回答by Henry Hammond
If your date is in the format of a string use the explode function
如果您的日期是字符串格式，请使用爆炸函数
array explode ( string $delimiter , string $string [, int $limit ] )
//In the case of your code
$length = strrpos($oldDate," ");
$newDate = explode( "-" , substr($oldDate,$length));
$output = $newDate[2]."/".$newDate[1]."/".$newDate[0];
Hope the above works now
希望以上工作现在
回答by SeanJA
There is also the DateTimeobject if you want to go that way: http://www.php.net/manual/en/datetime.construct.php
DateTime如果你想这样做，也有对象：http: //www.php.net/manual/en/datetime.construct.php
回答by user3045510
Try this:
尝试这个：
$old_date = Date_create("2010-04-19 18:31:27");
$new_date = Date_format($old_date, "d/m/Y");
回答by Devang Patel
$source = 'your varible name';
$date = new DateTime($source);
$_REQUEST["date"] = $date->format('d-m-Y');
echo $_REQUEST["date"];
