使用 PHP 变量执行 Python 脚本
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Executing Python Script with PHP Variables
提问by Micah
I am writing a simple application that uses information from a form, passes it through $_POST to a PHP script that executes a python script and outputs the results. The problem I am having is that my python script is not actually running with the arguments being passed in.
我正在编写一个简单的应用程序，它使用表单中的信息，通过 $_POST 将其传递给执行 python 脚本并输出结果的 PHP 脚本。我遇到的问题是我的 python 脚本实际上并没有在传入参数的情况下运行。
process3.php file:
process3.php 文件：
<?php
$start_word = $_POST['start'];
$end_word = $_POST['end'];
echo "Start word: ". $start_word . "<br />";
echo "End word: ". $end_word . "<br />";
echo "Results from wordgame.py...";
echo "</br>";
$output = passthru('python wordgame2.py $start_word $end_word');
echo $output;
?>
Output:
输出：
Start word: dog
End word: cat
Results from wordgame.py...
Number of arguments: 1 arguments. Argument List: ['wordgame2.py']
At the top of my wordgame2.py, I have the following (for debugging purposes):
在我的 wordgame2.py 顶部，我有以下内容（用于调试）：
#!/usr/bin/env python
import sys
print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
Why isn't the number of arguments being passed = 3? (Yes, my form does send the data correctly.)
为什么传递的参数数量不是 3？（是的，我的表单确实正确发送了数据。）
Any help is greatly appreciated!
任何帮助是极大的赞赏！
Edit: I might add that it does run when I explicitly tell it the start and end word... something like this:
编辑：我可能会补充说，当我明确告诉它开始和结束词时，它确实会运行......像这样：
$output = passthru('python wordgame2.py cat dog');
echo $output
采纳答案by shad0w_wa1k3r
Update -
更新 -
Now that I am aware of PHP, the mistake lies in using the single-quotes '. In PHP, single quoted strings are considered literals, PHP does not evaluate the content inside it. However, double quoted "strings are evaluated and would work as you are expecting them to. This is beautifully summarized in this SO answer. In our case,
现在我知道 PHP，错误在于使用单引号'. 在 PHP 中，单引号字符串被视为文字，PHP 不会评估其中的内容。但是，双引号"字符串会被评估，并且会按照您的预期工作。这在这个 SO answer 中得到了很好的总结。在我们的例子中，
$output = passthru("python wordgame2.py $start_word $end_word");
would work, but the following won't -
会工作，但以下不会 -
$output = passthru('python wordgame2.py $start_word $end_word');
Original answer -
原答案——
I think the mistake lies in
我认为错误在于
$output = passthru("python wordgame2.py $start_word $end_word");
Try this
尝试这个
$output = passthru("python wordgame2.py ".$start_word." ".$end_word);
回答by Micah
Thank you for your contributions. I have figured out my problem with this simple fix:
感谢你的贡献。我已经通过这个简单的修复解决了我的问题：
$command = 'python wordgame2.py ' . $start_word . ' ' . $end_word;
$output = passthru($command);
In order for passthru to properly handle the php variables, it needs to be concatenated into the string before executing.
为了让 passthru 正确处理 php 变量，它需要在执行之前连接成字符串。
