Bash 中的“[0：找不到命令”
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"[0: command not found" in Bash
提问by Dhaval Babu
I am trying to get the array in the while-loop and need to update the value in array too.
我试图在 while 循环中获取数组，并且也需要更新数组中的值。
Below is my code what I have tried. I get this error [0: command not found
下面是我尝试过的代码。我收到这个错误[0: command not found
#!/bin/bash
i=0
while [$i -le "{#myarray[@]}" ]
do
echo "Welcome $i times"
i= $(($i+1)))
done
How do I fix this?
我该如何解决？
回答by codeforester
Need a space after [and no space before or after =in the assignment. $(($i+1)))would try to execute the output of the ((...))expression and I am sure that's not what you want. Also, you are missing a $before the array name.
分配后需要一个空格，前后[没有空格=。$(($i+1)))会尝试执行((...))表达式的输出，我确定这不是您想要的。此外，您$在数组名称之前缺少一个。
With these things corrected, your while loop would be:
纠正这些事情后，您的 while 循环将是：
#!/bin/bash
i=0
while [ "$i" -le "${#myarray[@]}" ]
do
echo "Welcome $i times"
i=$((i + 1))
done
i=$((i + 1))can also be written as((i++))- it is always better to enclose variables in double quotes inside
[ ... ] - check your script through shellcheck- you can catch most basic issues there
i=$((i + 1))也可以写成((i++))- 将变量用双引号括起来总是更好
[ ... ] - 通过shellcheck检查您的脚本- 您可以在那里发现最基本的问题
See also:
也可以看看：
