Javascript 过滤器阵列不在另一个阵列中

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时间:2020-08-23 15:14:40  来源:igfitidea点击:

Filter Array Not in Another Array

javascriptknockout.js

提问by Peru

Need to filter one array based on another array. Is there a util function in knock out ? else i need to go with javascript

需要根据另一个数组过滤一个数组。击倒中是否有 util 函数?否则我需要使用 javascript

First :

第一的 :

var obj1 = [{
    "visible": "true",
    "id": 1
}, {
    "visible": "true",
    "id": 2
}, {
    "visible": "true",
    "id": 3
}, {
    "Name": "Test3",
    "id": 4
}];

Second :

第二 :

var obj2 = [ 2,3]

Now i need to filter obj1 based on obj2 and return items from obj1 that are not in obj2 omittng 2,3 in the above data (Comparison on object 1 Id)

现在我需要根据 obj2 过滤 obj1 并从 obj1 返回上面数据中不在 obj2 omitng 2,3 中的项目(对象 1 Id 的比较)

output:

输出:

[{
    "visible": "true",
    "id": 1
}, {
    "Name": "Test3",
    "id": 4
}];

回答by Joseph

You can simply run through obj1using filterand use indexOfon obj2to see if it exists. indexOfreturns -1if the value isn't in the array, and filterincludes the item when the callback returns true.

您可以简单地运行obj1usingfilter和 use indexOfonobj2来查看它是否存在。indexOf返回-1如果该值不是在阵列中,并且filter包括所述项目时回调返回true

var arr = obj1.filter(function(item){
  return obj2.indexOf(item.id) === -1;
});


With newer ES syntax and APIs, it becomes simpler:

使用更新的 ES 语法和 API,它变得更简单:

const arr = obj1.filter(i => !obj2.includes(i.id))

回答by Marwan Sulaiman

To create your output array, create a function that will iterate through obj1 and populate a new array based on whether the id of every obj in the iteration exists in obj2.

要创建您的输出数组,请创建一个函数,该函数将遍历 obj1 并根据迭代中每个 obj 的 id 是否存在于 obj2 中来填充一个新数组。

var obj1 = [{
    "visible": "true",
    "id": 1
}, {
    "visible": "true",
    "id": 2
}, {
    "visible": "true",
    "id": 3
}, {
    "Name": "Test3",
    "id": 4
}];

var obj2 = [2,3]

var select = function(arr) {
  var newArr = [];
  obj1.forEach(function(obj) {
    if obj2.indexOf(obj.id) !== -1 {
      newArr.push(obj)
    };
  };
  return newArr;
};