如何在 Scala 中将 Long 转换为 Int？
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How to cast Long to Int in Scala?
提问by Ivan
I'd like to use the folowing function to convert from Joda Time to Unix timestamp:
我想使用以下函数将 Joda 时间转换为 Unix 时间戳：
def toUnixTimeStamp(dt : DateTime) : Int = {
val millis = dt.getMillis
val seconds = if(millis % 1000 == 0) millis / 1000
else { throw new IllegalArgumentException ("Too precise timestamp") }
if (seconds > 2147483647) {
throw new IllegalArgumentException ("Timestamp out of range")
}
seconds
}
Time values I intend to get are never expected to be millisecond-precise, they are second-precise UTC by contract and are to be further stored (in a MySQL DB) as Int, standard Unix timestamps are our company standard for time records. But Joda Time only provides getMillis and not getSeconds, so I have to get a Long millisecond-precise timestamp and divide it by 1000 to produce a standard Unix timestamp.
我打算获得的时间值永远不会精确到毫秒，它们是合约上精确到秒的 UTC 并且将进一步存储（在 MySQL 数据库中）作为 Int，标准 Unix 时间戳是我们公司的时间记录标准。但是 Joda Time 只提供 getMillis 而不是 getSeconds，所以我必须得到一个 Long 毫秒级的时间戳并将它除以 1000 以生成一个标准的 Unix 时间戳。
And I am stuck making Scala to make an Int out of a Long value. How to do such a cast?
我坚持让 Scala 从 Long 值中生成一个 Int 。这样的演员怎么演？
回答by Luigi Plinge
Use the .toIntmethod on Long, i.e. seconds.toInt
使用.toIntLong上的方法，即seconds.toInt
