jQuery AJAX - 在成功和错误中获取响应体
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AJAX - get response body in success and error
提问by Ulug'bek Ro'zimboyev
I am apologize for the stupid question, but I need your help. I need to get information about response inside AJAX.
我为这个愚蠢的问题道歉，但我需要你的帮助。我需要获取有关内部响应的信息AJAX。
$.ajax({
type: "POST",
url: '/register',
data : registerRequestJSON,
contentType:"application/json",
success: function(data){
$("#register_area").text();// need to show success
},
error: function(err) {
$("#register_area").text("@text"); // @text = response error, it is will be errors: 324, 500, 404 or anythings else
}
});
How can I use response body? (documentation Jquary.Ajaxis not working at the momment)
如何使用响应体？（文档 Jquary.Ajax目前不起作用）
回答by Arun P Johny
The first param to error handler is jqxhr, it has the property responseTextwhich will give the response body.
错误处理程序的第一个参数是jqxhr，它具有responseText提供响应正文的属性。
$.ajax({
type: "POST",
url: '/register',
data : registerRequestJSON,
contentType:"application/json",
success: function(data){
$("#register_area").text();// need to show success
},
error: function(jqxhr) {
$("#register_area").text(jqxhr.responseText); // @text = response error, it is will be errors: 324, 500, 404 or anythings else
}
});
