bash 在两个单独的变量中获取 curl 响应的标题和正文？
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Get both the headers and the body of a curl response in two separated variables?
提问by Daniel
I am looking for a way to make ONE curl call and get to variables from it: one with the headers and another with the response body.
我正在寻找一种方法来进行一次 curl 调用并从中获取变量：一个带有标题，另一个带有响应正文。
I've found several questions asking about how to separate headers from body, but people seems only interested in one of them. I need both headers and body.
我发现了几个关于如何将标题与正文分开的问题，但人们似乎只对其中一个感兴趣。我需要标题和正文。
I cannot use an external file to store the body (thus using -o $file is not an option).
我不能使用外部文件来存储正文（因此不能使用 -o $file ）。
I can use
我可以用
headers=$(curl -D /dev/stdout $URL)
to get the headers into one variable, but how can I redirect the output to another variable?
将标题放入一个变量中，但如何将输出重定向到另一个变量？
Thanks a lot!
非常感谢！
采纳答案by glenn Hymanman
head=true
while IFS= read -r line; do
if $head; then
if [[ -z $line ]]; then
head=false
else
headers+=("$line")
fi
else
body+=("$line")
fi
done < <(curl -sD - "$url" | sed 's/\r$//')
printf "%s\n" "${headers[@]}"
echo ===
printf "%s\n" "${body[@]}"
To join the elements of an array into a single scalar variable:
要将数组元素连接到单个标量变量中：
the_body=$( IFS=$'\n'; echo "$body[*]" )
In bash4.3, you can use named references to simplify switching from "header" mode to "body" mode:
在bash4.3 中，您可以使用命名引用来简化从“header”模式到“body”模式的切换：
declare -n section=headers
while IFS= read -r line; do
if [[ $line = $'\r' ]]; then
declare -n section=body
fi
section+=("$line")
done < <(curl -sD - "$url")
For some reason, glenn Hymanman's answer did not catch the body part of the response. I had to separate the curl request into another command expansion and then enclose it in double quotes. Then I did not use arrays, but simply concatenated values to the variables. This works for me:
出于某种原因，格伦Hyman曼的回答没有抓住响应的主体部分。我不得不将 curl 请求分成另一个命令扩展，然后用双引号将其括起来。然后我没有使用数组，而是简单地将值连接到变量。这对我有用：
output=$(curl -si -d "" --request POST https://$url)
head=true
while read -r line; do
if $head; then
if [[ $line = $'\r' ]]; then
head=false
else
header="$header"$'\n'"$line"
fi
else
body="$body"$'\n'"$line"
fi
done < <(echo "$output")
Thank you, Glenn!
谢谢你，格伦！
回答by 0x10203040
I would like to share a way to parse curl response without any external program, bash only.
我想分享一种无需任何外部程序（仅 bash）即可解析 curl 响应的方法。
First, get the response of a curl request passing -sw "%{http_code}".
首先，获取传递的 curl 请求的响应-sw "%{http_code}"。
res=$(curl -sw "%{http_code}" $url)
The result will be a string containing the body followed by the http code.
结果将是一个包含正文后跟 http 代码的字符串。
Then, get the http code:
然后，获取http代码：
http_code="${res:${#res}-3}"
And the body:
还有身体：
if [ ${#res} -eq 3 ]; then
body=""
else
body="${res:0:${#res}-3}"
fi
Note that if the length of http_code and response are equal (length 3), body is empty. Else, just strip out the http code and you get the body.
注意，如果 http_code 和 response 的长度相等（长度为 3），则 body 为空。否则，只需去掉 http 代码即可获得正文。
