C++ 错误：没有匹配的函数调用'min(long unsigned int&, unsigned int&)'
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error: no matching function for call to ‘min(long unsigned int&, unsigned int&)’
提问by Will
I'm using ubuntu 12.04 - 64 bits. I tested it with boost 1.46, 1.48, 1.52 and gcc 4.4 and 4.6 When I try to compile:
我正在使用 ubuntu 12.04 - 64 位。我用 boost 1.46、1.48、1.52 和 gcc 4.4 和 4.6 对其进行了测试当我尝试编译时：
while (m_burstReqBeatsRemain) {
if (m_burstReqAddress % m_dramRowSize == 0) {
m_admRequestQueue.push_back(adm_request());
adm_request &req = m_admRequestQueue.back();
req.address = m_burstReqAddress;
req.command = tlm::TLM_READ_COMMAND;
//call to min function
req.readLen = std::min(m_burstReqBeatsRemain * sizeof(Td), m_dramRowSize);
}
m_burstReqBeatsRemain--;
m_burstReqAddress += sizeof(Td);
m_ocpTxnQueue.push_back(m_ocpReq);
}
I get this error:
我收到此错误：
no matching function for call to ‘min(long unsigned int&, unsigned int&)
from /usr/include/c++/4.6/bits/stl_algobase.h*
Note: with ubuntu 12.04 32 bits works fine
注意：使用 ubuntu 12.04 32 位工作正常
Any idea how I can fix this?
知道我该如何解决这个问题吗？
回答by Nawaz
std::minis a function template on Twhich is the type of bothparameters of the function. But you seem to pass function arguments of different type, andrely on template argument deduction from function arguments, which is not possible.
std::min是一个函数模板，T其上是函数的两个参数的类型。但是您似乎传递了不同类型的函数参数，并依赖于从函数参数中推导出模板参数，这是不可能的。
So the fix is :
所以修复是：
Either don't rely on template argument deduction, instead explicitly mention the template argument:
std::min<unsigned long>(ulongarg, uintarg); //ok //^^^^^^^^^^^^^^^ //don't rely on template argument deduction //instead pass template argument explicitly.Or pass function arguments of same type:
std::min(ulongarg, static_cast<unsigned long>(uintarg)); //ok //^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ //pass both arguments of same type
要么不依赖模板参数推导，而是明确提及模板参数：
std::min<unsigned long>(ulongarg, uintarg); //ok //^^^^^^^^^^^^^^^ //don't rely on template argument deduction //instead pass template argument explicitly.或者传递相同类型的函数参数：
std::min(ulongarg, static_cast<unsigned long>(uintarg)); //ok //^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ //pass both arguments of same type
