php 删除多个空格
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Remove multiple whitespaces
提问by creativz
I'm getting $row['message']from a MySQL database and I need to remove all whitespace like \n\tand so on.
我$row['message']从 MySQL 数据库中获取，我需要删除所有空格\n\t，诸如此类。
$row['message'] = "This is a Text \n and so on \t Text text.";
should be formatted to:
应格式化为：
$row['message'] = 'This is a Text and so on Text text.';
I tried:
我试过：
$ro = preg_replace('/\s\s+/', ' ',$row['message']);
echo $ro;
but it doesn't remove \nor \t, just single spaces. Can anyone tell me how to do that?
但它不会删除\nor \t，只是单个空格。谁能告诉我怎么做？
回答by codaddict
You need:
你需要：
$ro = preg_replace('/\s+/', ' ',$row['message']);
You are using \s\s+which means whitespace(space, tab or newline) followed by one or more whitespace. Which effectively means replace two or more whitespace with a single space.
您正在使用\s\s+这意味着空格（空格、制表符或换行符）后跟一个或多个空格。这实际上意味着用一个空格替换两个或多个空格。
What you want is replace one or more whitespace with single whitespace, so you can use the pattern \s\s*or \s+(recommended)
您想要的是用单个空格替换一个或多个空格，因此您可以使用模式 \s\s*或\s+（推荐）
回答by Cez
<?php
$str = "This is a string with
spaces, tabs and newlines present";
$stripped = preg_replace(array('/\s{2,}/', '/[\t\n]/'), ' ', $str);
echo $str;
echo "\n---\n";
echo "$stripped";
?>
This outputs
这输出
This is a string with
spaces, tabs and newlines present
---
This is a string with spaces, tabs and newlines present
回答by Anonymous
preg_replace('/[\s]+/mu', ' ', $var);
\salready contains tabs and new lines, so this above regex appears to be sufficient.
\s已经包含制表符和新行，所以上面的正则表达式似乎就足够了。
回答by Lukas Liesis
simplified to one function:
简化为一个功能：
function removeWhiteSpace($text)
{
$text = preg_replace('/[\t\n\r$str='This is a Text \n and so on Text text.';
print preg_replace("/[[:blank:]]+/"," ",$str);
\x0B]/', '', $text);
$text = preg_replace('/([\s])+/', ' ', $text);
$text = trim($text);
return $text;
}
based on Danuel O'Neal answer.
基于 Danuel O'Neal 的回答。
回答by ghostdog74
$x = "this \n \t\t \n works.";
var_dump(preg_replace('/\s\s+/', ' ', $x));
// string(11) "this works."
回答by nickf
I can't replicate the problem here:
我无法在这里复制问题：
'\n\t' != "\n\t"
I'm not sure if it was just a transcription error or not, but in your example, you're using a single-quoted string. \nand \tare only treated as new-line and tab if you've got a double quoted string. That is:
我不确定这是否只是转录错误，但在您的示例中，您使用的是单引号字符串。如果您有双引号字符串\n，\t则仅将其视为换行符和制表符。那是：
preg_replace('/(?:\s\s+|\n|\t)/', ' ', $x);
Edit: as Codaddict pointed out, \s\s+won't replace a single tab character. I still don't think using \s+is an efficient solution though, so how about this instead:
编辑：正如 Codacci 指出的那样，\s\s+不会替换单个制表符。我仍然不认为 using\s+是一个有效的解决方案，那么如何改为：
preg_replace('/(\s\s+|\t|\n)/', ' ', $row['message']);
回答by middus
<?php
#This should help some newbies
# REGEX NOTES FROM DANUEL
# I wrote these functions for my own php framework
# Feel Free to make it better
# If it gets more complicated than this. You need to do more software engineering/logic.
# (.) // capture any character
# // if it is followed by itself
# + // one or more
class whitespace{
static function remove_doublewhitespace($s = null){
return $ret = preg_replace('/([\s])+/', ' ', $s);
}
static function remove_whitespace($s = null){
return $ret = preg_replace('/[\s]+/', '', $s );
}
static function remove_whitespace_feed( $s = null){
return $ret = preg_replace('/[\t\n\r$str = "This is a Text \n and so on \t Text text.";
$str = str_replace(["\r", "\n", "\t"], " ", $str);
while (strpos($str, " ") !== false)
{
$str = str_replace(" ", " ", $str);
}
echo $str;
\x0B]/', '', $s);
}
static function smart_clean($s = null){
return $ret = trim( self::remove_doublewhitespace( self::remove_whitespace_feed($s) ) );
}
}
$string = " Hey yo, what's \t\n\tthe sc\r\nen\n\tario! \n";
echo whitespace::smart_clean($string);
This replaces all tabs, all newlines and all combinations of multiple spaces, tabs and newlines with a single space.
这将用一个空格替换所有制表符、所有换行符以及多个空格、制表符和换行符的所有组合。
回答by Danuel O'Neal
preg_replace('/\s+/', ' ',$data)
$data = 'This is a Text
and so on Text text on multiple lines and with whitespaces';
$data= preg_replace('/\s+/', ' ',$data);
echo $data;
回答by hharek
Without preg_replace()
没有 preg_replace()
##代码##