在 C++ 中初始化常量字符串的静态常量数组
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Initializing a static const array of const strings in C++
提问by Nick
I am having trouble initializing a constant array of constant strings.
我在初始化常量字符串的常量数组时遇到问题。
From week.h (showing only relevant parts):
从week.h（仅显示相关部分）：
class Week {
private:
static const char *const *days = { "mon", "tue", "wed", "thur",
"fri", "sat", "sun" };
};
When I compile I get the error "excess elements in scalar initializer". I tried making it type const char **, thinking I messed up the 2nd const placement, but I got the same error. What am I doing wrong?
编译时出现错误“标量初始值设定项中的元素过多”。我试着让它输入 const char **，以为我搞砸了第二个 const 位置，但我得到了同样的错误。我究竟做错了什么？
回答by Armen Tsirunyan
First of all, you need an array, not a pointer.
首先，你需要一个数组，而不是一个指针。
static const char * const days[] = {"mon", "tue", "wed", "thur",
"fri", "sat", "sun"};
Second of all, you can't initialize that directly inside the class definition. Inside the class definition, leave only this:
其次，您不能直接在类定义中对其进行初始化。在类定义中，只留下这个：
static const char * const days[]; //declaration
Then, in the .cpp file, write the definition
然后，在 .cpp 文件中，写入定义
const char * const Week::days[] = {"mon", "tue", "wed", "thur",
"fri", "sat", "sun"};
Update for C++11Now you can initialize members directly in the class definition:
C++11 更新现在您可以直接在类定义中初始化成员：
const char * const days[] = {"mon", "tue", "wed", "thur",
"fri", "sat", "sun"};
回答by marni
For C++11, you canmake the initialisation inside your class declaration, in your .hfile. However, you will need to include constexpr in your .cppfile too. Example for the case above:
对于C++11，您可以在.h文件中的类声明中进行初始化。但是，您还需要在.cpp文件中包含 constexpr 。上述案例的示例：
In your week.h file, write:
在您的 week.h 文件中，写入：
class Week {
public:
static const constexpr char* const days[] =
{ "mon", "tue", "wed", "thur","fri", "sat", "sun" };
};
In your week.cpp file, write somewhere:
在你的 week.cpp 文件中，写下某处：
constexpr const char* const Week::days[];
Make sure you enable C++11, e.g. compile with
确保您启用C++11，例如编译
g++ -std=c++11 week.cpp
g++ -std=c++11 week.cpp
