postgresql 如何在 Swift 中执行 GET 和 POST 请求?
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How do I perform GET and POST requests in Swift?
提问by Nathan McKaskle
I adapted this from Ray Wenderlich's iOS Apprentice tutorial part 4.
我改编自 Ray Wenderlich 的 iOS Apprentice 教程第 4 部分。
This code works as a GET request sent to my Strongloop API with a simple database model, however:
此代码用作发送到我的 Strongloop API 的 GET 请求,使用简单的数据库模型,但是:
This works, but I don't know why it works, since it invokes no method that I can see to actually send the request.
I see no means to make it into a POST request.
这有效,但我不知道它为什么有效,因为它没有调用我能看到的任何方法来实际发送请求。
我认为没有办法把它变成一个 POST 请求。
My question is: How do I perform a POST request? Is it done in a completely different way?
我的问题是:如何执行 POST 请求?它是以完全不同的方式完成的吗?
Let me know if you need more information.
如果您需要更多信息,请与我们联系。
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
// Do any additional setup after loading the view, typically from a nib.
}
override func didReceiveMemoryWarning() {
super.didReceiveMemoryWarning()
// Dispose of any resources that can be recreated.
}
@IBAction func getFromDB() {
let url = urlWithSearchText("")
println("URL: '\(url)'")
if let jsonString = performGetRequestWithURL(url) {
println("Received JSON string '\(jsonString)'")
}
}
func urlWithSearchText(searchText: String) -> NSURL {
let escapedSearchText = searchText.stringByAddingPercentEscapesUsingEncoding(NSUTF8StringEncoding)!
let urlString = String(format: "http://localhost:3000/api/Tests", escapedSearchText)
let url = NSURL(string: urlString)
return url!
}
func performGetRequestWithURL(url: NSURL) -> String? {
var error: NSError?
if let resultString = String(contentsOfURL: url, encoding: NSUTF8StringEncoding, error: &error) {
return resultString
} else if let error = error {
println("Download Error: \(error)")
} else {
println("Unknown Download Error")
}
return nil
}
Here is a picture of this working:
这是该工作的图片:
https://dl.dropboxusercontent.com/u/14464971/Images/Messages%20Image%281477993527%29.png
https://dl.dropboxusercontent.com/u/14464971/Images/Messages%20Image%281477993527%29.png
采纳答案by Peder Wessel
Below are two POST methods. Depending on if you want it synchronous (everything else waits until the post method is completed) or asynchronous (POST method runs in background, other methods run in parallel).
下面是两种 POST 方法。取决于您希望它是同步的(其他一切都等待 post 方法完成)还是异步的(POST 方法在后台运行,其他方法并行运行)。
Methods
方法
// POST data to url
func postDataAsynchronous(url: String, bodyData: String, completionHandler: (responseString: String!, error: NSError!) -> ()) {
var URL: NSURL = NSURL(string: url)!
var request:NSMutableURLRequest = NSMutableURLRequest(URL:URL)
request.HTTPMethod = "POST";
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()){
response, data, error in
var output: String!
if data != nil {
output = NSString(data: data, encoding: NSUTF8StringEncoding) as! String
}
completionHandler(responseString: output, error: error)
}
}
// Obtain the data
func postDataSynchronous(url: String, bodyData: String, completionHandler: (responseString: String!, error: NSError!) -> ())
{
let URL: NSURL = NSURL(string: url)!
var request:NSMutableURLRequest = NSMutableURLRequest(URL:URL)
request.HTTPMethod = "POST"
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);
request.addValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
var response: NSURLResponse?
var error: NSError?
// Send data
let data = NSURLConnection.sendSynchronousRequest(request, returningResponse: &response, error: &error)
var output: String! // Default to nil
if data != nil{
output = NSString(data: data!, encoding: NSUTF8StringEncoding) as! String
}
completionHandler(responseString: output, error: error)
}
Using them
使用它们
You can then call (use) them like so:
然后你可以像这样调用(使用)它们:
postDataSynchronous(url, bodyData: bodyData) {
responseString, error in
if error != nil {
println("Error during post: \(error)")
return
}
else{
//Success
println(responseString)
userType = responseString // Set usertype based on server response
}
}
SWIFT 2.0
斯威夫特 2.0
func postData(url: String, params: Dictionary<String, String>, completionHandler: (data: NSData?, response: NSURLResponse?, error: NSError?) -> ()) {
// Indicate download
UIApplication.sharedApplication().networkActivityIndicatorVisible = true
let url = NSURL(string: url)!
// print("URL: \(url)")
let request = NSMutableURLRequest(URL: url)
let session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
// Verify downloading data is allowed
do {
request.HTTPBody = try NSJSONSerialization.dataWithJSONObject(params, options: [])
} catch let error as NSError {
print("Error in request post: \(error)")
request.HTTPBody = nil
} catch {
print("Catch all error: \(error)")
}
// Post the data
let task = session.dataTaskWithRequest(request) { data, response, error in
completionHandler(data: data, response: response, error: error)
// Stop download indication
UIApplication.sharedApplication().networkActivityIndicatorVisible = false // Stop download indication
}
task.resume()
}
回答by Suhit Patil
Swift 3 & above
Swift 3 及以上
GET
得到
private func httpRequest() {
//create the url with NSURL
let url = URL(string: "https://jsonplaceholder.typicode.com/todos/1")! //change the url
//create the session object
let session = URLSession.shared
//now create the URLRequest object using the url object
let request = URLRequest(url: url)
//create dataTask using the session object to send data to the server
let task = session.dataTask(with: request as URLRequest, completionHandler: { data, response, error in
guard error == nil else {
return
}
guard let data = data else {
return
}
do {
//create json object from data
if let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as? [String: Any] {
print(json)
}
} catch let error {
print(error.localizedDescription)
}
})
task.resume()
}
POST
邮政
@IBAction func submitAction(sender: AnyObject) {
//declare parameter as a dictionary which contains string as key and value combination. considering inputs are valid
let parameters = ["name": nametextField.text, "password": passwordTextField.text] as Dictionary<String, String>
//create the url with URL
let url = URL(string: "http://myServerName.com/api")! //change the url
//create the session object
let session = URLSession.shared
//now create the URLRequest object using the url object
var request = URLRequest(url: url)
request.httpMethod = "POST" //set http method as POST
do {
request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: .prettyPrinted) // pass dictionary to nsdata object and set it as request body
} catch let error {
print(error.localizedDescription)
}
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
//create dataTask using the session object to send data to the server
let task = session.dataTask(with: request as URLRequest, completionHandler: { data, response, error in
guard error == nil else {
return
}
guard let data = data else {
return
}
do {
//create json object from data
if let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as? [String: Any] {
print(json)
// handle json...
}
} catch let error {
print(error.localizedDescription)
}
})
task.resume()
}
回答by user9476144
guard let url = URL(string: "https://jsonplaceholder.typicode.com/users") else { return }
let session = URLSession.shared
session.dataTask(with: url) { (data, response, error) in
if let response = response {
print(response)
}
if let data = data {
print(data)
do {
let json = try JSONSerialization.jsonObject(with: data, options: [])
print(json)
} catch {
print(error)
}
}
}.resume()
}
It's a get method.
这是一个获取方法。
回答by user9476144
let parameters = ["username": "@Bipin_kumar", "tweet": "HelloWorld"]
guard let url = URL(string: "https://jsonplaceholder.typicode.com/posts") else { return }
var request = URLRequest(url: url)
request.httpMethod = "POST"
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
guard let httpBody = try? JSONSerialization.data(withJSONObject: parameters, options: []) else { return }
request.httpBody = httpBody
let session = URLSession.shared
session.dataTask(with: request) { (data, response, error) in
if let response = response {
print(response)
}
if let data = data {
do {
let json = try JSONSerialization.jsonObject(with: data, options: [])
print(json)
} catch {
print(error)
}
}
}.resume()
It's a post method.
这是一种post方法。
回答by Shakti
GET Request
获取请求
func getRequest(with url: URL, callback: @escaping (Any?) -> Swift.Void) -> Void {
let defaultConfigObject = URLSessionConfiguration.default
defaultConfigObject.timeoutIntervalForRequest = 30.0
defaultConfigObject.timeoutIntervalForResource = 60.0
let session = URLSession.init(configuration: defaultConfigObject, delegate: nil, delegateQueue: nil)
var urlRequest = URLRequest(url: url as URL)
urlRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
urlRequest.httpMethod = "GET"
session.dataTask(with: urlRequest, completionHandler: { (data, response, error) in
guard let httpResponse: HTTPURLResponse = response as? HTTPURLResponse
else {
print("Error: did not receive data")
return
}
var response : (Any)? = nil
if httpResponse.statusCode == 200 {
print(httpResponse)
guard let responseData = data else {
print("Error: did not receive data")
return
}
do {
let responseData = try JSONSerialization.jsonObject(with: responseData, options: [JSONSerialization.ReadingOptions.allowFragments])
response = responseData
callback(response)
}
catch _ as NSError {
let responseString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
callback(responseString)
return
}
}
else {
print(httpResponse)
guard error == nil else {
print("error calling GET on /todos/1")
print(error ?? "error")
callback(response!)
return
}
}
}).resume()
}
POST REQUEST
发布请求
//MARK: post request
func postRequest(with url:URL, postBody:String, callback: @escaping (Any?) -> Void) -> Void {
let defaultConfigObject = URLSessionConfiguration.default
defaultConfigObject.timeoutIntervalForRequest = 30.0
defaultConfigObject.timeoutIntervalForResource = 60.0
let session = URLSession.init(configuration: defaultConfigObject, delegate: nil, delegateQueue: nil)
let params: String! = postBody
var urlRequest = URLRequest(url: url as URL)
urlRequest.httpMethod = "POST"
let data = params.data(using: String.Encoding(rawValue: String.Encoding.utf8.rawValue))
urlRequest.httpBody = data
session.dataTask(with: urlRequest, completionHandler: { (data, urlResponse, error) in
guard let httpResponse:HTTPURLResponse = urlResponse as? HTTPURLResponse
else{
print("did not get any data")
return
}
var response : (Any)? = nil
if httpResponse.statusCode == 200 {
guard let responseData = data else {
print("Error: did not receive data")
return
}
do {
guard let responseData = try JSONSerialization.jsonObject(with: responseData, options: []) as? [String: AnyObject] else {
print("error trying to convert data to JSON")
return
}
response = responseData
callback(response)
} catch _ as NSError {
let responseString = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
callback(responseString)
return
}
}
else {
guard error == nil else {
print("error calling GET on /todos/1")
print(error ?? "error")
callback(nil)
return
}
}
}).resume()
}
Always try to check the HTTPURLResponse code
总是尝试检查 HTTPURLResponse 代码
回答by Daniel Aquino
The String(contentsOfUrl:encoding:error) initializer makes a GET request under the hood and returns the content as a string with the specified encoding.
String(contentsOfUrl:encoding:error) 初始值设定项在后台发出 GET 请求,并将内容作为具有指定编码的字符串返回。
One way to make a request would be to create an NSURLConnection and use NSMutablrURLRequest set the HTTP method the post. With the NSMutableURLRequest, you can create a NSURLConnection and start it immediately with a delegate or you can call NSURLConnection.sendSynchronousRequest or NSURLConnection.sendAsynchronousRequest to send the request.
发出请求的一种方法是创建一个 NSURLConnection 并使用 NSMutablrURLRequest 设置帖子的 HTTP 方法。使用 NSMutableURLRequest,您可以创建一个 NSURLConnection 并立即使用委托启动它,或者您可以调用 NSURLConnection.sendSynchronousRequest 或 NSURLConnection.sendAsynchronousRequest 来发送请求。
回答by nRewik
This method invokes the http request.
此方法调用 http 请求。
String(contentsOfURL: url, encoding: NSUTF8StringEncoding, error: &error)
Because Swift String
has no init signature like this.
因为 SwiftString
没有这样的 init 签名。
This method would be written somewhere in the project, as extension
of String
这种方法将在地方项目中写的,为extension
的String
It would be something like this
它会是这样的
extension String{
init(contentsOfURL: NSURL, encoding: NSUTF8StringEncoding, inout error: NSError){
// load data from url
self = //parse data to string
}
}