javascript 通过ajax到PHP的多维数组
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Multidimensional Arrays via ajax to PHP
提问by Zac
Ok seriously struggling here. I am having some problems trying to send a multdimensional array to PHP via ajax. Here's what I have been trying:
好吧,在这里认真挣扎。我在尝试通过 ajax 将多维数组发送到 PHP 时遇到了一些问题。这是我一直在尝试的:
To simplify rather than copy paste a wall of code:
为了简化而不是复制粘贴代码墙:
peoplearray[0] = [name] => 'john'
[age] => '28'
[sex] => 'Male'
peoplearray[1] = [name] => 'julie'
[age] => '20'
[sex] => 'Female'
main_array['item'] = 'x';
main_array['something'] = 'x';
main_array['another'] = 'x';
I want to get this to php via post
. I figured I may aswell just join them together as I am multidimensional anyway thus :
我想通过post
. 我想我也可以将它们连接在一起,因为无论如何我都是多维的:
main_array['peoplearray'] = peoplearray;
now to do the ajax:
现在做ajax:
// var data = JSON.stringify(main_array);
var send = $.ajax({
type: "POST",
cache: false,
url: "theurl",
data: {data:main_array} //I do change this `main_array` when using the above stringify!
});
send.done(function(msg) {
console.log(msg);
})
in PHP I am just doing the following right now:
在 PHP 中,我现在正在执行以下操作:
$data= $_POST['data'];
print_r($data);
in firebug: (an empty string)
在萤火虫中: (an empty string)
when I have the var data = JSON.stringify(main_array);
uncommented I get the following: [][
当我var data = JSON.stringify(main_array);
取消注释时,我得到以下信息:[][
if i add $data = json_decode($_POST['data']);
to the php I get:
如果我添加$data = json_decode($_POST['data']);
到 php 我得到:
Array ( )
Basically the main_array
I realise does not need to be an array and so I can get that stuff across no problem but what I need to do is get the peoplearray
over so that I can do some foreach
etc... with it in php. Any help would be much appreciated I am sure I am just being stupid!
基本上,main_array
我意识到不需要是一个数组,所以我可以毫无问题地解决这些问题,但我需要做的是peoplearray
结束,以便我可以foreach
在 php.ini 中做一些等...... 任何帮助将不胜感激我相信我只是愚蠢!
EDIT: The reasoning behind this is that peoplearray
could have 0 or 100 entries so I just need to get it to php so I can foreach
it to do the DB inputs. If there is a better approach I would be very grateful to hear it as I am still pretty new to this.
编辑:这背后的原因是它peoplearray
可能有 0 或 100 个条目,所以我只需要将它放到 php 中,这样我就可以foreach
执行数据库输入。如果有更好的方法,我会很感激听到它,因为我对此还是很陌生。
EDIT: Thanks to Nicola's answer everything is passing fine except the important part which is mainarry.peoplearray - it is not appearing in the the return console.log
and I cant access it in PHP. Any solutions on this or do I have to put the foreach intelligence in the javascript and just send everything individually?
编辑:感谢 Nicola 的回答,除了 mainarry.peoplearray 的重要部分之外,一切都很好——它没有出现在返回中console.log
,我无法在 PHP 中访问它。对此有任何解决方案,还是我必须将 foreach 智能放在 javascript 中并单独发送所有内容?
采纳答案by Zac
I got it to work by keeping the peoplearray
seperate.
我通过保持peoplearray
独立来让它工作。
So I did as Nicola said and created mainarray
as an object ie. declaring with curlies: {}
所以我按照 Nicola 说的做了,并创建mainarray
了一个对象,即。用卷曲声明:{}
The peoplearray
I left as an array ie declaring with []
, however then name,age&sex
fields I created as an object ie. {} and then .push()
them into the the peoplearray
.
的peoplearray
余留作为阵列即具有声明[]
,但是然后name,age&sex
字段我作为对象,即创建。{} 然后将.push()
它们放入peoplearray
.
Then the ajax looked as follows:
然后ajax看起来如下:
var send = $.ajax({
type: "POST",
dataType: "json",
cache: false,
url: "theurl",
data: {data:main_array, people:peoplearray}
});
then with the PHP everything is available in the $_POST, and if you
然后用 PHP 一切都在 $_POST 中可用,如果你
echo json_encode($people); //or whatever var name it is stored as in the php
the objects ie name,age,sex
properties are shown in the
对象即name,age,sex
属性显示在
send.done(function(msg) {
console.log(msg);
})
回答by Nicola Peluchetti
First of all main_array
is not an array but an object because in javascript there are no associative arrays and for this reason
首先main_array
不是数组而是对象,因为在 javascript 中没有关联数组,因此
main_array['peoplearray'] = peoplearray;
is equivalent to
相当于
main_array.peoplearray = peoplearray;
and you should declare main_array like this
你应该像这样声明 main_array
var main_array = {};
then try to change your function like this:
然后尝试像这样更改您的功能:
var send = $.ajax({
type: "POST",
dataType: "json",
cache: false,
url: "theurl",
data: {data:main_array}
});
and server side
和服务器端
header('Content-type: application/json');
$data= $_POST['data'];
echo json_encode($data);