php Zend 控制器中 url() 辅助函数的等价物
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Equivalent of url() helper function in Zend controller
提问by Mathew Attlee
In the Zend view helper, there is the function url() for outputting a URL based on the routing tables eg
在 Zend 视图助手中，有函数 url() 用于根据路由表输出 URL，例如
$this->url(array('controller' => 'comments', 'action' => 'add')
How can I do the same thing in a controller? In particular I want to set the action URL for a Zend Form using controller/action syntax rather than a standard URL eg
我怎样才能在控制器中做同样的事情？特别是我想使用控制器/操作语法而不是标准 URL 为 Zend 表单设置操作 URL，例如
$form = new Zend_Form;
$form->setMethod('post')->setAction( $this->url(array('controller' => 'comments', 'action' => 'add')) );
回答by Ferdinand Beyer
There is an action helper for this: Zend_Controller_Action_Helper_Url. Inside an action controller, you can access it using:
有此一动作助手：Zend_Controller_Action_Helper_Url。在动作控制器中，您可以使用以下方法访问它：
$this->_helper->url($action [, $controller [, $module [, $params]]]);
or:
或者：
$this->_helper->url->url(array(...));
Alternatively, you can also use the view helper:
或者，您也可以使用视图助手：
$this->view->url(...);
回答by Attilio
I've actually found out that only this works:
我实际上发现只有这样有效：
// in your form
public function init()
{
$router = Zend_Controller_Front::getInstance()->getRouter();
$url = $router->assemble(
array(
'paramterName0' => 'parameterValue0',
'paramterName1' => 'parameterValue1',
),
'routeName'
);
$this->setAction($url);
...
}
回答by Mathew Attlee
Was able to answer my own question as it seems the following code does the trick:-
能够回答我自己的问题，因为似乎以下代码可以解决问题：-
$form = new Zend_Form;
$form->setMethod('post')->setAction( $this->getHelper('url')->url(array('controller' => 'index', 'action' => 'add')) );
回答by Andrii Krot
In zf3 you can use:
在 zf3 中，您可以使用：
$form = new YourFormClass();
$form->setMethod('post')->setAction($this->url()->fromRoute(array('controller' => 'index', 'action' => 'add'));
