Javascript 使用 Node.JS，如何获取按时间顺序排列的文件列表？

Using Node.JS, how do you get a list of files in chronological order?

提问by Newtang

For a given directory, how can I get a list of files in chronological order (by date-modified) in Node.JS? I didn't see anything in the File System docs.

对于给定的目录，如何在 Node.JS 中按时间顺序（按修改日期）获取文件列表？我在文件系统文档中没有看到任何内容。

回答by cliffs of insanity

Give this a shot.

试一试。

var dir = './'; // your directory

var files = fs.readdirSync(dir);
files.sort(function(a, b) {
               return fs.statSync(dir + a).mtime.getTime() - 
                      fs.statSync(dir + b).mtime.getTime();
           });

I used the "sync" version of the methods. You should make them asynchronous as needed. (Probably just the readdirpart.)

我使用了这些方法的“同步”版本。您应该根据需要使它们异步。（可能只是readdir一部分。）

---

---

You can probably improve performance a bit if you cache the stat info.

如果您缓存统计信息，您可能会稍微提高性能。

var files = fs.readdirSync(dir)
              .map(function(v) { 
                  return { name:v,
                           time:fs.statSync(dir + v).mtime.getTime()
                         }; 
               })
               .sort(function(a, b) { return a.time - b.time; })
               .map(function(v) { return v.name; });

回答by Krzysztof Rosiński

Async version (2018)

异步版本 (2018)

const fs = require('fs');
const path = require('path');
const util = require('util');

const readdirAsync = util.promisify(fs.readdir);
const statAsync = util.promisify(fs.stat);

async function readdirChronoSorted(dirpath, order) {
  order = order || 1;
  const files = await readdirAsync(dirpath);
  const stats = await Promise.all(
    files.map((filename) =>
      statAsync(path.join(dirpath, filename))
        .then((stat) => ({ filename, stat }))
    )
  );
  return stats.sort((a, b) =>
    order * (b.stat.mtime.getTime() - a.stat.mtime.getTime())
  ).map((stat) => stat.filename);
}

(async () => {
  try {
    const dirpath = path.join(__dirname);
    console.log(await readdirChronoSorted(dirpath));
    console.log(await readdirChronoSorted(dirpath, -1));
  } catch (err) {
    console.log(err);
  }
})();

回答by Ismael Martinez

I ended up using underscore as gives the opportunity to account for what stat to use for the sorting.

我最终使用下划线，因为有机会说明用于排序的统计数据。

1st get the files in the directory using files = fs.readFileSync(directory);(you might want to try catch err in case directory does not exist or read permissions)

1st 获取目录中的文件使用files = fs.readFileSync(directory);（如果目录不存在或读取权限，您可能想尝试 catch err）

Then pass them to a function like the following one. That will return you the ordered list.

然后将它们传递给如下所示的函数。这将返回有序列表。

function orderByCTime(directory, files) {
    var filesWithStats = [];
    _.each(files, function getFileStats(file) {
        var fileStats = fs.statSync(directory + file);

        filesWithStats.push({
            filename: file,
            ctime: fileStats.ctime
        });
        file = null;
    });
    return _.sortBy(filesWithStats, 'ctime').reverse();
}

Underscore sort by asc by default. I reverse it as I need it descending order.

下划线默认按 asc 排序。我将其反转，因为我需要它以降序排列。

You could decide to sort by another stat (check node fs documentation here). I choose to use ctime as it should account for "touching" the file also.

您可以决定按另一个统计信息排序（在此处查看节点 fs 文档）。我选择使用 ctime，因为它也应该考虑“触摸”文件。

Hope helps,

希望有所帮助，

回答by Chase

Have you tried fs.readdir()?

你试过fs.readdir()吗？

http://nodejs.org/docs/v0.3.1/api/fs.html#fs.readdir

http://nodejs.org/docs/v0.3.1/api/fs.html#fs.readdir