Java 正则表达式否定整个词？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/23724661/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Regex to negate the whole word?
提问by user3198603
String test1 = "This is my test string";
I want to match a string which does not contain "test"
我想匹配一个不包含“test”的字符串
I can do it with
我可以做到
Pattern p = Pattern.compile(".*?^(test).*?")
and it works but at most of sites like Regular Expressions and negating a whole character group^(?!.*test).*$is suggested which did not work for me.
它可以工作，但在大多数网站（如正则表达式）和否定整个字符组^(?!.*test).*$的建议中，这对我不起作用。
As per my understanding ^(test)is sufficient so why ^(?!.*test).*$is required?
根据我的理解^(test)就足够了，为什么 ^(?!.*test).*$需要？
回答by hwnd
You want the following instead.
您想要以下内容。
^(?:(?!test).)*$
Regular expression:
正则表达式：
^ the beginning of the string
(?: group, but do not capture (0 or more times)
(?! look ahead to see if there is not:
test 'test'
) end of look-ahead
. any character except \n
)* end of grouping
$ before an optional \n, and the end of the string
With using ^(test), it is only looking for testat the beginning of the string, not negating it.
使用 using ^(test)，它只在字符串的开头寻找test，而不是否定它。
The negation ^operator will only work inside of a character class [^ ], but whole words do not work inside of a character class. For example [^test]matches any character except: (t, e, s, t)
否定^运算符只能在字符类内部工作[^ ]，但整个单词在字符类内部不起作用。例如[^test]匹配任何字符，除了： ( t, e, s, t)
回答by SocketM
.*= anything zero or more times
.*= 零次或多次
The Regex:
正则表达式：
^((?!test).)*$
I misunderstand it. Now I think it will work.
我误解了。现在我认为它会起作用。
