从 BASH 中的变量中删除 %0D
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Remove %0D from variable in BASH
提问by rdshck
I'm trying this:
我正在尝试这个：
token=`curl -I --header "X-Auth-User: [email protected]" --header "X-Auth-Key: XXXXXXXXXXXXXXXXXXXXXX" api.server.com | grep -Fi X-Auth-Token | awk -F" " '{ print }'`
/usr/bin/wget --accept .jpg,.jpeg -p "https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=$token" -O "image.jpg" || rm "image.jpg"
But my token result is:
但我的令牌结果是：
https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=SERVER_018d8100000000001d1b817f7d58a6%0D
Instead of:
代替：
https://api.server.com/v1/stats/1/graph?callback=jQuery171027000000144289315_1380000003353&mnum=1&res_type=cpu&g_type=6h&graph_type=img&full=1&w=515&h=150&X-Auth-Token=SERVER_018d8100000000001d1b817f7d58a6
How to remove %0D (Carriage return)?
如何删除 %0D（回车）？
回答by that other guy
You can add | tr -d '\r'to your curl pipeline to strip any carriage returns.
您可以添加| tr -d '\r'到 curl 管道以去除任何回车。
回答by crafter
There is a utility called dos2unix. You may have to install it. or use the translate
有一个名为 dos2unix 的实用程序。您可能必须安装它。或使用翻译
tr -d '\r' < input > output
EDIT Found a post that discusses a few options: Remove carriage return in Unix
编辑找到了一篇讨论几个选项的帖子： 在 Unix 中删除回车
回答by Ken Sharp
I solved it by piping to sed. I was already using sedin my pipe so it made sense.
我通过管道解决了它sed。我已经sed在我的管道中使用了，所以这是有道理的。
cmd | sed 's/\r//g'
cmd | sed 's/\r//g'
