ios 如何检查 NSString 是否包含 NSArray 中的 NSStrings 之一？
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原文地址: http://stackoverflow.com/questions/4702359/
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How to check if an NSString contains one of the NSStrings in an NSArray?
提问by Josh
I'm making an iOS app and I need to figure out if an NSStringcontains any of the NSStringsin an NSArray.
我在做iOS应用程序，我需要弄清楚如果NSString包含任何NSStrings在NSArray。
回答by Nick Moore
BOOL found=NO;
for (NSString *s in arrayOfStrings)
{
if ([stringToSearchWithin rangeOfString:s].location != NSNotFound) {
found = YES;
break;
}
}
回答by Adam
It may be a silly optimization for your use case, but depending on how large the array is that you are iterating, it may be helpful/more performant to use NSArray'sindexOfObjectWithOptions:passingTest:method.
对于您的用例来说，这可能是一个愚蠢的优化，但是根据您要迭代的数组有多大，使用NSArray'sindexOfObjectWithOptions:passingTest:方法可能会有所帮助/性能更高。
With this method you pass some options and a block that contains your test. Passing the NSEnumerationConcurrentoption will allow the evaluation of your block to occur on multiple threads concurrently and potentially speed things up. I reused invariant's test, but in a slightly different way. The block functionally returns a BOOL similar to the "found" variable in invariant's implementation. The "*stop = YES;" line indicates that iterating should stop.
使用这种方法，您可以传递一些选项和一个包含您的测试的块。传递该NSEnumerationConcurrent选项将允许您的块的评估同时发生在多个线程上，并可能加快速度。我重用了不变量的测试，但方式略有不同。该块在功能上返回一个类似于 invariant 实现中的“found”变量的 BOOL。“*stop = YES;” 线表示迭代应该停止。
See the NSArray reference documentation for more info. Reference
有关更多信息，请参阅 NSArray 参考文档。参考
NSArray *arrayOfStrings = ...;
NSString *stringToSearchWithin = ...";
NSUInteger index = [arrayOfStrings indexOfObjectWithOptions:NSEnumerationConcurrent
passingTest:^(id obj, NSUInteger idx, BOOL *stop)
{
NSString *s = (NSString *)obj;
if ([stringToSearchWithin rangeOfString:s].location != NSNotFound) {
*stop = YES;
return YES;
}
return NO;
}];
if (arrayOfStrings == nil || index == NSNotFound)
{
NSLog(@"The string does not contain any of the strings from the arrayOfStrings");
return;
}
NSLog(@"The string contains '%@' from the arrayOfStrings", [arrayOfStrings objectAtIndex:index]);
回答by C?ur
Very small security improvement on Adam's answer: there is a big issue with "objectAtIndex:" because it is totally not thread-safe and will make your app crash much too often. So I do:
Adam 回答的安全性改进非常小：“objectAtIndex:”存在一个大问题，因为它完全不是线程安全的，并且会使您的应用程序经常崩溃。所以我这样做：
NSArray *arrayOfStrings = ...;
NSString *stringToSearchWithin = ...";
__block NSString *result = nil;
[arrayOfStrings indexOfObjectWithOptions:NSEnumerationConcurrent
passingTest:^(NSString *obj, NSUInteger idx, BOOL *stop)
{
if ([stringToSearchWithin rangeOfString:obj].location != NSNotFound)
{
result = obj;
*stop = YES;
//return YES;
}
return NO;
}];
if (!result)
NSLog(@"The string does not contain any of the strings from the arrayOfStrings");
else
NSLog(@"The string contains '%@' from the arrayOfStrings", result);
回答by Bruno
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF IN %@", theArray];
BOOL result = [predicate evaluateWithObject:theString];
回答by Alexander
As with the release of iOS8, Apple added a new method to NSStringcalled localizedCaseInsensitiveContainsString. This will exactly do what you want way easier:
随着 iOS8 的发布，Apple 添加了一个新的方法来NSString调用localizedCaseInsensitiveContainsString. 这将完全满足您的要求：
BOOL found = NO;
NSString *string = @"ToSearchFor";
for (NSString *s in arrayOfStrings){
if ([string localizedCaseInsensitiveContainsString:s]) {
found = YES;
break;
}
}
