C++ WinAPI：创建具有指定客户区大小的窗口
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4843806/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
WinAPI: Create a window with a specified client area size
提问by GeReV
I was wondering how can I create a window using Win32 API with a specific client area size.
我想知道如何使用具有特定客户区大小的Win32 API 创建窗口。
When trying to create a window using the following piece of code, the entire window is 640x480, with the window's chrome taking some of the client area:
尝试使用以下代码创建窗口时，整个窗口为 640x480，窗口的镶边占据了一些客户区：
HWND hWnd;
WNDCLASSEX WndClsEx;
ZeroMemory(&WndClsEx, sizeof(WNDCLASSEX));
WndClsEx.cbSize = sizeof(WNDCLASSEX);
WndClsEx.style = CS_HREDRAW | CS_VREDRAW;
WndClsEx.lpfnWndProc = DefWindowProc;
WndClsEx.cbClsExtra = 0;
WndClsEx.cbWndExtra = 0;
WndClsEx.hIcon = LoadIcon(NULL, IDI_APPLICATION);
WndClsEx.hCursor = LoadCursor(NULL, IDC_ARROW);
WndClsEx.hbrBackground = (HBRUSH)GetStockObject(WHITE_BRUSH);
WndClsEx.lpszMenuName = NULL;
WndClsEx.lpszClassName = TEXT("Title");
WndClsEx.hInstance = hInstance;
WndClsEx.hIconSm = LoadIcon(NULL, IDI_APPLICATION);
RegisterClassEx(&WndClsEx);
hWnd = CreateWindowEx( NULL,
TEXT("Title"),
TEXT("Title"),
WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT,
CW_USEDEFAULT,
640,
480,
NULL,
NULL,
hInstance,
NULL);
Assuming simple math won't quite solve the problem, how do I take the chrome size into account?
假设简单的数学不能完全解决问题，我该如何考虑镀铬尺寸？
Note:I'm using SDL after creating the window, but I'm guessing it's bound to the window size and makes no difference to its size.
注意：我在创建窗口后使用 SDL，但我猜它绑定到窗口大小并且对其大小没有影响。
回答by Ferruccio
You can use the AdjustWindowRector AdjustWindowRectExfunction to calculate the window size given a desired client area size.
您可以使用AdjustWindowRect或AdjustWindowRectEx函数来计算给定所需客户区大小的窗口大小。
