C++ 11：使用成员函数和 this 作为参数启动线程
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C++ 11 : Start thread with member function and this as parameter
提问by juanchopanza
Using this code, I got and error :
使用此代码，我得到了错误：
Error 1 error C2064: term does not evaluate to a function taking 1 arguments c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline
错误 1 错误 C2064：术语未计算为采用 1 个参数的函数 c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline
class PipelineJob {
private:
std::thread *thread;
void execute(PipelineJob* object);
public:
void execute(PipelineJob* object)
{
}
PipelineJob()
{
this->thread = new std::thread(&PipelineJob::execute, this);
}
};
I tried many variation, any one now how to solve this?
我尝试了很多变体，现在有人如何解决这个问题？
回答by juanchopanza
Removing the templates and the pointers for simplicity, this is more or less what you would want:
为简单起见删除模板和指针，这或多或少是您想要的：
class PipelineJob
{
private:
std::thread thread_;
void execute(PipelineJob* object) { ..... }
public:
PipelineJob()
{
thread_ = std::thread(&PipelineJob::execute, this, this);
}
~PipelineJob() { thread_.join(); }
};
Note that thisis passed two times to the std::threadconstructor: once for the member function's implicit first parameter, the second for the visible parameter PipelineJob* objectof the member function.
请注意，this向std::thread构造函数传递了两次：一次用于成员函数的隐式第一个参数，第二次用于PipelineJob* object成员函数的可见参数。
If your executemember function does not need an external PipelineJobpointer, then you would need something like
如果您的execute成员函数不需要外部PipelineJob指针，那么您将需要类似
class PipelineJob
{
private:
std::thread thread_;
void execute() { ..... }
public:
PipelineJob()
{
thread_ = std::thread(&PipelineJob::execute, this);
}
~PipelineJob() { thread_.join(); }
};
