php 如何同时遍历两个数组而不重新遍历父循环？
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How can I iterate through two arrays at the same time without re-iterating through the parent loop?
提问by Rogers
How can I iterate through two arrays at the same time that have equal sizes ?
如何同时迭代具有相同大小的两个数组？
for example , first array $a = array( 1,2,3,4,5);second array $b = array(1,2,3,4,5);
例如，第一个数组$a = array( 1,2,3,4,5);第二个数组$b = array(1,2,3,4,5);
The result that I would like through iterating through both is having the looping process going through the same values to produce a result like
我希望通过迭代两者的结果是让循环过程通过相同的值来产生类似的结果
1-1
2-2
3-3
4-4
5-5
I tried to do it this way below but it didn't work , it keeps going through the first loop again
我尝试在下面这样做，但没有用，它再次通过第一个循环
foreach($a as $content) {
foreach($b as $contentb){
echo $a."-".$b."<br />";
}
}
回答by Nick Andriopoulos
Use a normal forloop instead of a foreach, so that you get an explicit loop counter:
使用普通for循环而不是 a foreach，以便获得显式循环计数器：
for($i=0; $i<count($content)-1; $i++) {
echo $content[$i].'-'.$contentb[$i];
}
If you want to use string based indexed arrays, and know that the string indexes are equal between arrays, you can stick with the foreachconstruct
如果你想使用基于字符串的索引数组，并且知道数组之间的字符串索引是相等的，你可以坚持使用foreach构造
foreach($content as $key=>$item) {
echo $item.'-'.$contentb[$key];
}
回答by Mark Baker
Not the most efficient, but a demonstration of SPL's multipleIterator
不是最有效的，而是 SPL 的 multipleIterator 的演示
$mi = new MultipleIterator();
$mi->attachIterator(new ArrayIterator($a));
$mi->attachIterator(new ArrayIterator($b));
$newArray = array();
foreach ( $mi as $value ) {
list($value1, $value2) = $value;
echo $value1 , '-' , $value2 , PHP_EOL;
}
回答by LuaWeaver
If they're the same size, just do this:
如果它们的大小相同，请执行以下操作：
foreach($a as $key => $content){
$contentb = $b[$key];
echo($content."-".$contentb."<br />");
}
