Python：使用正则表达式获取列表索引？
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Python: get list indexes using regular expression?
提问by AP257
In Python, how do you get the position of an item in a list (using list.index) using fuzzy matching?
在 Python 中，如何list.index使用模糊匹配（使用）获取项目在列表中的位置？
For example, how do I get the indexes of all fruit of the form *berryin the following list?
例如，如何获取*berry以下列表中所有水果的索引？
fruit_list = ['raspberry', 'apple', 'strawberry']
# Is it possible to do something like the following?
berry_fruit_at_positions = fruit_list.index('*berry')
Anyone have any ideas?
谁有想法？
采纳答案by eumiro
Try:
尝试：
fruit_list = ['raspberry', 'apple', 'strawberry']
[ i for i, word in enumerate(fruit_list) if word.endswith('berry') ]
returns:
返回：
[0, 2]
Replace endswithwith a different logic according to your matching needs.
endswith根据您的匹配需求替换为不同的逻辑。
回答by Steven Rumbalski
With regular expressions:
使用正则表达式：
import re
fruit_list = ['raspberry', 'apple', 'strawberry']
berry_idx = [i for i, item in enumerate(fruit_list) if re.search('berry$', item)]
And without regular expressions:
并且没有正则表达式：
fruit_list = ['raspberry', 'apple', 'strawberry']
berry_idx = [i for i, item in enumerate(fruit_list) if item.endswith('berry')]
回答by Dorian Grv
with a function :
有一个功能：
import re
fruit_list = ['raspberry', 'apple', 'strawberry']
def grep(yourlist, yourstring):
ide = [i for i, item in enumerate(yourlist) if re.search(yourstring, item)]
return ide
grep(fruit_list, "berry$")
