Laravel Eloquent - 在哪里
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/28633389/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Laravel Eloquent - Where In All
提问by musaya
In Laravel 4.2, I am trying to achieve a query that returns all users, that have all of certain activities. As of now, I have a query that returns all users that have one of many activities:
在Laravel 4.2 中,我试图实现一个返回所有用户的查询,这些用户具有所有某些活动。到目前为止,我有一个查询返回所有具有许多活动之一的用户:
//$selectedActivities being an array
$userByActivities = User::with('activities')
->whereHas('activities', function($query) use($selectedActivities){
$query->whereIn('id', $selectedActivities);
})->get();
To be more clear: given activities a,b,c. I am looking for all users that have activity a AND b AND c. My query returns all users that have activity a OR b OR c.
更清楚地说:给定活动a,b,c。我正在寻找具有活动a AND b AND c 的所有用户。我的查询返回所有具有活动a OR b OR c 的用户。
Thank you for your help.
感谢您的帮助。
EDIT:
编辑:
The solution offered by lukasgeiterresults in following query:
lukasgeiter提供的解决方案导致以下查询:
select * from `users` where
(select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '7') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '3') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '1') >= 1
and (select count(*) from `activities` inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id` where `activity_user`.`user_id` = `users`.`id` and `id` = '2') >= 1
Whereas the solution offered by Jarek Tkaczyk:
而Jarek Tkaczyk提供的解决方案:
$userByActivities = User::with('activities')
->whereHas('activities', function($query) use($selectedActivities) {
$query->selectRaw('count(distinct id)')->whereIn('id', $selectedActivities);
}, '=', count($selectedActivities))->get();
for a similar request, results in following query:
对于类似的请求,会产生以下查询:
select * from `users` where (select count(distinct id) from `activities`
inner join `activity_user` on `activities`.`id` = `activity_user`.`activity_id`
where `activity_user`.`user_id` = `users`.`id` and `id` in ('7', '3', '1', '2')) = 4
回答by lukasgeiter
You'll have to add multiple whereHas
for that:
您必须为此添加多个whereHas
:
$query = User::with('activities');
foreach($selectedActivities as $activityId){
$query->whereHas('activities', function($q) use ($activityId){
$q->where('id', $activityId);
});
}
$userByActivities = $query->get();
回答by Victor Priceputu
If you are getting Cardinality violation: 1241 Operand should contain 2 column(s)
the problem is the nested selectCount
adds to the normal select count(*)
instead of overriding the existing select, so changing to $query->distinct()->whereIn('id', $selectedActivities);
did the trick for me, or changing to $query->select(DB::raw(count(distinct id)))
如果您遇到Cardinality violation: 1241 Operand should contain 2 column(s)
问题是嵌套selectCount
添加到法线select count(*)
而不是覆盖现有选择,因此更改为$query->distinct()->whereIn('id', $selectedActivities);
对我有用,或更改为$query->select(DB::raw(count(distinct id)))