PHP 读取目录和排序
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PHP readdir and sort
提问by
I'm making a little gallery. I want to read the file names off a directory and print the file names below after I've stripped some leading numerals and file extensions.
我正在做一个小画廊。我想从目录中读取文件名，并在去掉一些前导数字和文件扩展名后打印下面的文件名。
I have two versions of the code.
我有两个版本的代码。
Version 1 doesn't sort
版本 1 不排序
$current_dir = "$DOCUMENT_ROOT"."/weddings2/";
$dir = opendir($current_dir); // Open the sucker
while ($file = readdir($dir)) // while loop
{
$parts = explode(".", $file); // pull apart the name and dissect by period
if (is_array($parts) && count($parts) > 1) { // does the dissected array have more than one part
$extension = end($parts); // set to we can see last file extension
$bfile= substr($file, 2); //strips the first two characters
$cfile= preg_replace(('/\d/'),' ',$bfile);//remove numbers
$cfile= preg_replace(('/_/'),' ',$cfile);
$cfile= preg_replace(('/.jpg/'),' ',$cfile);
if ($extension == "jpg" OR $extension == "JPG") // is extension ext or EXT ?
echo "<td><img src=\"weddings2/$file\"><br />$cfile</td>\n";
}
}
closedir($dir); // Close the directory after we are done
Version 2 sorts but I can't manipulate the file names
版本 2 排序，但我无法操作文件名
$current_dir = "$DOCUMENT_ROOT"."/weddings2/";
$dir = opendir($current_dir); // Open the sucker
$files = array();
while ($files[] = readdir($dir));
sort($files);
closedir($dir);
foreach ($files as $file)
if ($file <> "." && $file <> ".." && !preg_match("/^hide/i",$file))
$table_cell .= "<td><img src='".'weddings2/'. rawurlencode($file) ."'><br />$cfile</td>\n";
echo $table_cell;
Yes, I know I'm dumb. Arghhh!
是的，我知道我很笨。啊！
回答by Vinko Vrsalovic
EDIT: Your code is missing braces
编辑：您的代码缺少大括号
You have
你有
foreach (...)
code
code
and it should be
它应该是
foreach (...) {
code
code
}
Just put the code between $parts and the last $cfile after the foreach loop, just add the braces in the loop so you can put more code in. Also note that you have different if conditions in both code snippets, you have to decide which one use or if to combine them both into a single condition.
只需将代码放在 $parts 和 foreach 循环后的最后一个 $cfile 之间，只需在循环中添加大括号即可放入更多代码。 另请注意，两个代码片段中的 if 条件不同，您必须决定哪个一种用途或 if 将它们组合成一个条件。
$current_dir = "$DOCUMENT_ROOT"."/weddings2/";
$dir = opendir($current_dir); // Open the sucker
$files = array();
while ($files[] = readdir($dir));
sort($files);
closedir($dir);
foreach ($files as $file) {
//MANIPULATE FILENAME HERE, YOU HAVE $file...
if ($file <> "." && $file <> ".." && !preg_match("/^hide/i",$file))
echo "<td><img src='".'weddings2/'. rawurlencode($file) ."'><br />$cfile</td>\n";
}
回答by Vinko Vrsalovic
Since the comment section doesn't have enough room...
由于评论区没有足够的空间......
Vinko: I'm editing here to make it easier. You should have
Vinko：我在这里编辑是为了让它更容易。你应该有
$current_dir = "$DOCUMENT_ROOT"."/weddings2/";
$dir = opendir($current_dir); // Open the sucker
$files = array();
while ($files[] = readdir($dir));
sort($files);
closedir($dir);
foreach ($files as $file)
{
$bfile= substr($file, 2); //strips the first two characters
$cfile= preg_replace(('/\d/'),' ',$bfile);
$cfile= preg_replace(('/_/'),' ',$cfile);
$cfile= preg_replace(('/.jpg/'),' ',$cfile);
if ($file <> "." && $file <> ".." && !preg_match("/^hide/i",$file))
// echo "<td><img src=\"weddings2/$file\"><br />$cfile</td>\n";
//echo "<td><img src=\"weddings2/$file\"><br />$cfile</td>\n";
$table_cell .= "<td><img src='".'weddings2/'. rawurlencode($file) ."'><br />$cfile</td>\n";
//$table_cell .= " <li><a href='" .'pdfs/'. rawurlencode($file) ."'>$file</a></li>\n";
echo $table_cell;
}
instead of what you tried
而不是你尝试过的
I tried this:
我试过这个：
$current_dir = "$DOCUMENT_ROOT"."/weddings2/";
$dir = opendir($current_dir); // Open the sucker
$files = array();
while ($files[] = readdir($dir));
sort($files);
closedir($dir);
foreach ($files as $file)
$bfile= substr($file, 2); //strips the first two characters
$cfile= preg_replace(('/\d/'),' ',$bfile);
$cfile= preg_replace(('/_/'),' ',$cfile);
$cfile= preg_replace(('/.jpg/'),' ',$cfile);
if ($file <> "." && $file <> ".." && !preg_match("/^hide/i",$file))
// echo "<td><img src=\"weddings2/$file\"><br />$cfile</td>\n";
//echo "<td><img src=\"weddings2/$file\"><br />$cfile</td>\n";
$table_cell .= "<td><img src='".'weddings2/'. rawurlencode($file) ."'><br />$cfile</td>\n";
//$table_cell .= " <li><a href='" .'pdfs/'. rawurlencode($file) ."'>$file</a></li>\n";
echo $table_cell;
And got this
得到了这个
<pre>
<td><img src='weddings2/36%20And%20they%20lived%20happily%20ever%20after.jpg'><br /> And they lived happily ever after </td></pre>
Instead of this:
取而代之的是：
<pre>
<td><img src="weddings2/05Wedding_Chapel.jpg"><br />Wedding Chapel </td>
<td><img src="weddings2/06Bride_Flowers.jpg"><br />Bride Flowers </td>
<td><img src="weddings2/09%20Bridemaids%20on%20the%20lawn.jpg"><br /> Bridemaids on the lawn </td>
<td><img src='weddings2/36%20And%20they%20lived%20happily%20ever%20after.jpg'><br /> And they lived happily ever after </td>
</pre>
