显示 Bash 命令的输出并将输出保存在变量中
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/2081830/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Display output of a Bash command and keeping the output in a variable
提问by Selmak
I'm not sure if it is possible but what I want to do is to run a bash command and storing the output in a variable AND display it as if I launched the command normally. Here is my code:
我不确定是否有可能，但我想要做的是运行 bash 命令并将输出存储在变量中并显示它，就像我正常启动命令一样。这是我的代码：
VAR=`svn checkout $URL`
So I want to store the output in VAR and still see the result (and because svn checkout takes a long time, I can't do echo $VAR just after..)
所以我想将输出存储在 VAR 中并仍然看到结果（并且因为 svn checkout 需要很长时间，我不能在之后执行 echo $VAR ..）
Thanks
谢谢
回答by Alok Singhal
If the command is run from a terminal, you can do:
如果命令是从终端运行的，您可以执行以下操作：
VAR=$(svn checkout $URL | tee /dev/tty)
回答by Paused until further notice.
You don't have to call the external tee:
您不必致电外部tee：
VAR=$(svn checkout $URL) && echo $VAR
or even:
甚至：
VAR=$(svn checkout $URL); echo $VAR
