java 以编程方式关闭显示在 JDialog 中的 JPanel
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原文地址: http://stackoverflow.com/questions/10936306/
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programmatically close a JPanel which is displayed in JDialog
提问by gtiwari333
I have a main application frame (MainFrame class). On actionperformed event of a JButton, a JPanel (MyJPanel class)is opened by placing it in JDialog. I am not extending JDialogto create MyJPanelclass because I might need MyJPanel at other purposes too.
我有一个主应用程序框架 ( MainFrame class)。在 a 的 actionperformed 事件上JButton， a JPanel (MyJPanel class)通过将其放入 来打开JDialog。我没有扩展JDialog创建MyJPanel类，因为我可能也需要 MyJPanel 用于其他目的。
My Problem is I cannot programmatically close the MyJPanelwhich is displayed in JDialog. Is there anything that I missing? Could you please figure it out?
我的问题是我不能以编程方式关闭MyJPanel其显示在JDialog。有什么我想念的吗？你能弄清楚吗？
import java.awt.EventQueue;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JDialog;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.WindowConstants;
public class MainFrame extends JPanel {
public MainFrame() {
JButton btnOpenJdialog = new JButton("Open JDialog");
add(btnOpenJdialog);
btnOpenJdialog.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
JDialog jd = new JDialog();
MyJPanel mjp = new MyJPanel(true);//showing in JDialog
jd.setTitle("JDialog");
jd.add(mjp);
jd.pack();
jd.setVisible(true);
}
});
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
public void run() {
createAndShowGUI();
}
});
}
public static void createAndShowGUI() {
JFrame frame = new JFrame("Test-JFrame");
frame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);
frame.getContentPane().add(new MainFrame());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
}
MyJPanel Class :
MyJPanel 类：
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JPanel;
import javax.swing.JButton;
public class MyJPanel extends JPanel {
private boolean isShownInJDialog = false;
public MyJPanel() {
JButton btnCloseMe = new JButton("Finish Action");
add(btnCloseMe);
btnCloseMe.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
if (isShownInJDialog) {
MyJPanel.this.setVisible(false);
//how to close the JDialog too.
}
else {
//just hide the content,
MyJPanel.this.setVisible(false);
}
}
});
}
public MyJPanel(boolean isShownInJDialog) {
this();
this.isShownInJDialog = isShownInJDialog;
}
}
UPDATEI was able to solve this using Howard's answer as :
更新我能够使用霍华德的回答来解决这个问题：
...
if (isShownInJDialog) {
Window w = SwingUtilities.getWindowAncestor(MyJPanel.this);
w.setVisible(false);
}
...
回答by Howard
If I understand your question correctly, you want to close the JDialogwhich your MyJPanelis contained in but do not have a reference to it?
如果我没有理解你的问题，你要关闭的JDialog，你的MyJPanel是包含在，但没有提到它？
You may either provide such a reference using the constructor of MyJPanelor change the code inside your ActionListenerto
您可以使用 的构造函数提供这样的引用，也可以MyJPanel将内部代码更改ActionListener为
Window w = SwingUtilities.getWindowAncestor(MyJPanel.this);
w.setVisible(false);
which looks up the parent window of your panel without direct reference.
它在没有直接参考的情况下查找面板的父窗口。
