如何在 Laravel 5 控制器中复制文件
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How to copy files in laravel 5 controller
提问by paranoid
I want copy file to folder in laravel. when I copy file show me this error
我想将文件复制到 Laravel 中的文件夹。当我复制文件时向我显示此错误
The second argument to copy() function cannot be a directory
copy() 函数的第二个参数不能是目录
My code:
我的代码：
$success = \File::copy(base_path('test.text'),base_path('public/'));
回答by Ben Rhys-Lewis
The error says what it means. If you read the docs on the copy()function it states you must copy from a file to a new file. Eg copying content from a .txt file to another.txt file.
错误说明了它的含义。如果您阅读关于copy()函数的文档，它会指出您必须从文件复制到新文件。例如，将内容从 .txt 文件复制到另一个 .txt 文件。
So just add test.text after the public part and it will create a new file or overwrite an existing one.
所以只需在公共部分后添加 test.text ，它就会创建一个新文件或覆盖现有文件。
$success = \File::copy(base_path('test.text'),base_path('public/test.text'));
回答by Kalpesh Rajai
You can use the public_path()function to get the path to the public/folder you can copy that file like this
您可以使用该public_path()功能获取public/文件夹的路径，您可以像这样复制该文件
$destinationPath=public_path()."/UploadFolderName/FileName.ext";
$success = \File::copy(base_path('test.text'),$destinationPath);
now the questionis where is your source file? if it is already in the public folderthan you get the full path of that file like this.
现在question你在哪里source file？如果它已经在public folder比你得到该文件的完整路径，像这样。
$sourceFilePath=public_path()."/SomeFolderName/FileName";
$destinationPath=public_path()."//UploadFolderName/FileName.ext";
$success = \File::copy($sourceFilePath,$destinationPath);
Happy Coding!!!
编码快乐！！！
EDIT
编辑
public_path()is laravelinbuilt function that give the full pathof the publicfolder. for more information read here: https://laravel.com/docs/5.2/helpers#method-public-path
public_path()是laravel，让全内置功能path的的public文件夹中。有关更多信息，请阅读此处：https: //laravel.com/docs/5.2/helpers#method-public-path
