Java 如何从我的 android 设备访问我的本地 REST api？
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How can I access my local REST api from my android device?
提问by Alien
I have a spring REST api running locally on my computer. I would like to consume this api for android development.
我有一个在我的计算机上本地运行的 spring REST api。我想使用这个 api 进行 android 开发。
Here is my get request:
这是我的获取请求：
public static String sendGet(final String url) {
StringBuilder result = new StringBuilder();
HttpURLConnection urlConnection = null;
try {
String apiUrl = getAbsoluteUrl(url); // concatenate uri with base url eg: localhost:8080/ + uri
URL requestUrl = new URL(apiUrl);
urlConnection = (HttpURLConnection) requestUrl.openConnection();
urlConnection.connect(); // no connection is made
InputStream in = new BufferedInputStream(urlConnection.getInputStream());
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
String line;
while ((line = reader.readLine()) != null) {
result.append(line);
}
} catch (Exception e) {
e.printStackTrace();
} finally {
urlConnection.disconnect();
}
return result.toString();
}
I can access my api via my device's browser. However, when I use this same url within the built apk to make the request, no connection is made.
我可以通过我设备的浏览器访问我的 api。但是，当我在构建的 apk 中使用相同的 url 发出请求时，没有建立连接。
My manifest includes:
我的清单包括：
<uses-permission android:name="android.permission.INTERNET"/>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
Side notes:
旁注：
I am connecting my device to my laptop running the rest api via usb. I am using the WLAN IPv4 address found by calling ipconfig.
我正在通过 USB 将我的设备连接到运行其余 API 的笔记本电脑。我正在使用通过调用 ipconfig 找到的 WLAN IPv4 地址。
Any tips in the right direction would be much appreciated - thanks!
任何方向正确的提示将不胜感激 - 谢谢！
Edit to include chrome browser (on android device) output from local REST api running on my laptop (A GET request to return default guest user information):
编辑以包含我的笔记本电脑上运行的本地 REST api 的 chrome 浏览器（在 android 设备上）输出（返回默认访客用户信息的 GET 请求）：
采纳答案by Alien
SOLVED if anyone is interested:
如果有人感兴趣，请解决：
I managed to fix this issue by extending the class my original sendGet(final String url)was in as follows HttpClientUsage extends AsyncTask<String, Void, String>more information and a tutorial can be found here: AsyncTask tutorial
我设法通过扩展我原来sendGet(final String url)所在的类来解决这个问题，HttpClientUsage extends AsyncTask<String, Void, String>更多信息和教程可以在这里找到：AsyncTask教程
I then had to configure my CORS settings on my local REST API as follows:
然后我必须在本地 REST API 上配置我的 CORS 设置，如下所示：
cors:
allowed-origins: "*"
allowed-methods: GET, PUT, POST, DELETE, OPTIONS
allowed-headers: "*"
exposed-headers:
allow-credentials: true
max-age: 1800
Thank you all for your help, it is much appreciated.
谢谢大家的帮助，非常感谢。
回答by Shadow Droid
Your rest url must be something like this- http://localhost:8080/yourRest/restMethod.
Instead of localhost url connect your mobile and local machine on same network(wifi network). Get the ip address of your local machine e.g 192.168.1.X...so now your end point url for rest will be http://192.168.1.X:8080/yourRest/restMethod
您的休息网址必须是这样的- http://localhost:8080/yourRest/restMethod。
而不是 localhost url 在同一网络（wifi 网络）上连接您的移动和本地机器。获取您本地机器的 IP 地址，例如 192.168.1.X...所以现在您的端点 url 将是http://192.168.1.X:8080/yourRest/restMethod
回答by Mrinmoy
Check your ip:- Steps to check ip (make sure you are connected to internet)
检查您的 ip：- 检查 ip 的步骤（确保您已连接到互联网）
- Open command prompt
- type ipconfig
- Ip is the highlighted one in image below
- 打开命令提示符
- 输入ipconfig
- Ip 是下图中突出显示的那个
Now make your url like this: http://192.168.240.2/index.html
现在让你的网址像这样：http://192.168.240.2/index.html
回答by rakesh kashyap
Let me tell you an easier way to do this. If you are using Android emulator you can use 10.0.2.2 as the IP address to connect to the host machine where your REST API is available.
让我告诉你一个更简单的方法来做到这一点。如果您使用 Android 模拟器，您可以使用 10.0.2.2 作为 IP 地址来连接到您的 REST API 可用的主机。
Similarly if you are using Genymotion which uses Oracle Virtualbox, you can use 10.0.3.2.
同样，如果您使用的是使用 Oracle Virtualbox 的 Genymotion，则可以使用 10.0.3.2。
