Java 类型“class *”尚未增强 JPA 异常
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原文地址: http://stackoverflow.com/questions/19042416/
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The type "class *" has not been enhanced JPA exception
提问by coderatchet
I am running WebSphere v8, and using JPA persistence in a Java EE 6 environment.
我正在运行 WebSphere v8，并在 Java EE 6 环境中使用 JPA 持久性。
When I attempt to run code that deals with a particular entity, I run into this exception:
当我尝试运行处理特定实体的代码时，我遇到了以下异常：
javax.ejb.EJBTransactionRolledbackException: nested exception is: javax.ejb.EJBTransactionRolledbackException: nested exception is: javax.ejb.EJBException: See nested exception; nested exception is: org.apache.openjpa.persistence.ArgumentException: The type "class au.com.combined.domain.changeroutine.ChangeRoutineConsumedPK" has not been enhanced.
javax.ejb.EJBTransactionRolledbackException：嵌套异常为：javax.ejb.EJBTransactionRolledbackException：嵌套异常为：javax.ejb.EJBException：参见嵌套异常；嵌套异常是：org.apache.openjpa.persistence.ArgumentException：类型“class au.com.combined.domain.changeroutine.ChangeRoutineConsumedPK”尚未增强。
However, this articlesays that my classes should already be enhanced at runtime. ChangeRoutineConsumedPK is an Embeddable Class. Could someone take a look at my class and tell me what i'm doing wrong? thank you.
但是，这篇文章说我的类应该已经在运行时增强了。ChangeRoutineConsumedPK 是一个可嵌入的类。有人可以看看我的班级并告诉我我做错了什么吗？谢谢你。
ChangeRoutineConsumed:
ChangeRoutineConsumed：
@Entity
@Table(name = ChangeRoutineConsumed.TABLE_NAME)
public class ChangeRoutineConsumed extends BaseBusinessObject {
public static final String TABLE_NAME = "COCHANGEROUTINECONSUMED";
@EmbeddedId
private ChangeRoutineConsumedPK id;
protected ChangeRoutineConsumed() {
super();
}
public ChangeRoutineConsumed(@Min(1) long changeRoutineId, @NotNull String consumedBy){
this(new ChangeRoutineConsumedPK(changeRoutineId, consumedBy));
}
public ChangeRoutineConsumed(@NotNull ChangeRoutineConsumedPK id){
super();
setId(id);
}
...
public int hashCode(){...};
public boolean equals(Object obj){...}
}
ChangeRoutineConsumedPK:
ChangeRoutineConsumedPK：
@Embeddable
public class ChangeRoutineConsumedPK {
@Column
private long changeRoutineId;
@Column
private String consumedBy;
public ChangeRoutineConsumedPK(){}
public ChangeRoutineConsumedPK(long changeRoutineId, String consumedBy) {
setChangeRoutineId(changeRoutineId);
setConsumedBy(consumedBy);
}
...
public int hashCode() {...}
public boolean equals(Object obj) {...}
}
采纳答案by coderatchet
The ChangeRoutineConsumedPK class was not added to the persistence.xml and i had turned off automatic class scanning.
ChangeRoutineConsumedPK 类没有添加到persistence.xml 中，我关闭了自动类扫描。
Adding the class to the persistence.xml fixed the problem
将类添加到persistence.xml 修复了问题
<persistence-unit ...>
...
<class>au.com.combined.domain.changeroutine.ChangeRoutineConsumedPK</class>
...
</persistence-unit>
回答by Dheeraj Pure
if you are executing from main class pass below parameter in execution java -javaagent:/openjpa.jar com.xyz.Main
如果您从主类中执行，则在执行时传递以下参数 java -javaagent:/openjpa.jar com.xyz.Main
if using eclipse give above value in run Configuration > arguments > VM arguments.
如果使用 Eclipse，请在运行配置 > 参数 > VM 参数中给出以上值。
