缺少类型说明符 - 假设为 int。注意：C++ 不支持 default-int
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missing type specifier - int assumed. Note: C++ does not support default-int
提问by Michael
I have a cpp file that contains the following:
我有一个包含以下内容的 cpp 文件：
char const* types[] = { "char", "short", "int", "long", "float", "double", "void"};
std::set<std::string> ReservedWords;
ReservedWords.insert(std::begin(types),std::end(types));
this gives an error missing type specifier - int assumed. Note: C++ does not support default-int
这给出了一个错误 missing type specifier - int assumed. Note: C++ does not support default-int
I have read that you can't write statements in a global scope, is this the case here ?
我读到您不能在全局范围内编写语句，这里是这种情况吗？
I don't completely understand the rule, and would like to know where its best to put this code ? (header file, inside a function etc...)
我不完全理解规则，想知道把这段代码放在哪里最好？（头文件，在函数内等......）
回答by Luchian Grigore
First, not that std::beginand std::endare C++11, so are you sure you have a compatible compiler and that you're compiling with C++11 support?
首先，不是那个，std::begin而且std::end是 C++11，所以你确定你有一个兼容的编译器并且你是用 C++11 支持编译的吗？
I don't believe this is theerror though. Are you including:
我不相信这是在虽然错误。你包括：
#include <string>
#include <set>
#include <iterator>
?
?
回答by CB Bailey
char const* types[] = { "char", "short", "int", "long", "float", "double", "void"};
std::set<std::string> ReservedWords;
ReservedWords.insert(std::begin(types),std::end(types));
The first two lines here are declarations because they declare variables (typesand ReservedWords). The third line is not a declaration, it's just an expression statement so it's not legal for it to appear outside a function.
这里的前两行是声明，因为它们声明了变量（types和ReservedWords）。第三行不是声明，它只是一个表达式语句，所以它出现在函数之外是不合法的。
You could do something like:
你可以这样做：
char const* types[] = { "char", "short", "int", "long", "float", "double", "void"};
std::set<std::string> MakeReservedWords() {
std::set<std::string> tmp;
tmp.insert(std::begin(types), std::end(types));
return tmp;
}
std::set<std::string> ReservedWords(MakeReservedWords());
Given that you are using C++11 you should be able to do this:
鉴于您使用的是 C++11，您应该能够做到这一点：
std::set<std::string> ReservedWords { "char", "short", "int", "long", "float", "double", "void"};
If your compiler doesn't support this part of C++11 you will have to settle for something like this (as suggested by @juanchopanza):
如果您的编译器不支持 C++11 的这一部分，您将不得不接受这样的事情（如@juanchopanza 所建议的那样）：
char const* types[] = { "char", "short", "int", "long", "float", "double", "void"};
std::set<std::string> ReservedWords(std::begin(types), std::end(types));
回答by justcoder
This error appears when you don't include the correct files. Make sure to add #include <string.h>
当您不包含正确的文件时，会出现此错误。确保添加#include <string.h>
And yes, you must remove this line from global scope:
是的，您必须从全局范围中删除此行：
ReservedWords.insert(std::begin(types),std::end(types));
Try putting it in the main function.
试着把它放在主函数中。
