python中的列表有没有像.replace()这样的方法？
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Is there a method like .replace() for list in python?
提问by Patrick Tran
i've made a list out of a string using .split() method.
For example: string = " I like chicken" i will use .split() to make a list of words in the string ['I','like','chicken']Now if i want to replace 'chicken' with something else, what method i can use that is like .replace() but for a list?
我已经使用 .split() 方法从字符串中创建了一个列表。例如： string = "I like chicken" 我将使用 .split() 来制作字符串中的单词列表['I','like','chicken']现在如果我想用其他东西替换 'chicken'，我可以使用什么方法就像 .replace( ) 但对于一个列表？
回答by Ry-
There's nothing built-in, but it's just a loop to do the replacement in-place:
没有任何内置的东西，但它只是一个就地替换的循环：
for i, word in enumerate(words):
if word == 'chicken':
words[i] = 'broccoli'
or a shorter option if there's always exactly one instance:
如果总是只有一个实例，则使用更短的选项：
words[words.index('chicken')] = 'broccoli'
or a list comprehension to create a new list:
或列表理解来创建新列表：
new_words = ['broccoli' if word == 'chicken' else word for word in words]
any of which can be wrapped up in a function:
其中任何一个都可以包含在一个函数中：
def replaced(sequence, old, new):
return (new if x == old else x for x in sequence)
new_words = list(replaced(words, 'chicken', 'broccoli'))
回答by ShadowRanger
No such method exists, but a list comprehension can be adapted to the purpose easily, no new methods on listneeded:
不存在这样的方法，但是列表理解可以很容易地适应这个目的，不需要新的方法list：
words = 'I like chicken'.split()
replaced = ['turkey' if wd == "chicken" else wd for wd in words]
print(replaced)
Which outputs: ['I', 'like', 'turkey']
哪些输出： ['I', 'like', 'turkey']
