postgresql Sequelize ORM 中连接表的条件

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时间:2020-10-21 02:12:53  来源:igfitidea点击:

Where condition for joined table in Sequelize ORM

javascriptsqlpostgresqlormsequelize.js

提问by fourslashw

I want to get query like this with sequelize ORM:

我想使用 sequelize ORM 获得这样的查询:

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id"
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id"
WHERE ("B"."userId" = '100'
       OR "C"."userId" = '100')

The problem is that sequelise not letting me to reference "B" or "C" table in where clause. Following code

问题是续集不允许我在 where 子句中引用“B”或“C”表。以下代码

A.findAll({
    include: [{
        model: B,
        where: {
            userId: 100
        },
        required: false

    }, {
        model: C,
        where: {
            userId: 100
        },
        required: false
    }]
] 

gives me

给我

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id" AND "B"."userId" = 100
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id" AND "C"."userId" = 100

which is completely different query, and result of

这是完全不同的查询,结果

A.findAll({
    where: {
        $or: [
            {'"B"."userId"' : 100},
            {'"C"."userId"' : 100}
        ]
    },
    include: [{
        model: B,
        required: false

    }, {
        model: C,
        required: false
    }]
] 

is no even a valid query:

甚至没有一个有效的查询:

SELECT "A".*,      
FROM "A" 
LEFT OUTER JOIN "B" ON "A"."bId" = "B"."id"
LEFT OUTER JOIN "C" ON "A"."cId" = "C"."id"
WHERE ("A"."B.userId" = '100'
       OR "A"."C.userId" = '100')

Is first query even possible with sequelize, or I should just stick to raw queries?

使用 sequelize 甚至可以进行第一次查询,还是我应该坚持使用原始查询?

回答by Jan Aagaard Meier

Wrap the columns which reference joined tables in $$

包装引用连接表的列 $$

A.findAll({
    where: {
        $or: [
            {'$B.userId$' : 100},
            {'$C.userId$' : 100}
        ]
    },
    include: [{
        model: B,
        required: false

    }, {
        model: C,
        required: false
    }]
});