在 Laravel 控制器中不在对象上下文中时使用 $this
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Using $this when not in object context in a Laravel controller
提问by Rohansin
I created a public static function in a controller and I need to access a class property which is set on the constructor. I normally use $this->somethingto access such class properties, but this time, I got this error:
我在控制器中创建了一个公共静态函数，我需要访问在构造函数上设置的类属性。我通常$this->something用来访问这样的类属性，但这一次，我收到了这个错误：
Using
$thiswhen not in object context
使用
$this时没有对象上下文
Here's the code:
这是代码：
public static function PayExecute() {
$paymentId = Input::get('paymentId');
$PayerID = Input::get('PayerID');
$cont = $this->apiContext;
}
回答by V. Kovpak
You need $apiContextbe declared as static property, and you need use staticof selfkeyword. Something like this:
你需要$apiContext声明为静态属性，你需要使用static的self关键字。像这样的东西：
class YourController extends BaseController
{
private static $apiContext = '';
public static function PayExecute()
{
$paymentId = Input::get('paymentId');
$PayerID = Input::get('PayerID');
$cont = static::$apiContext;
}
}
BTW: Be aware about fact that staticis late static binding.
顺便说一句：注意static后期静态绑定的事实。
回答by NaeiKinDus
You cannot use "$this" in static methods. You do have access to "self::" though, but remember that you cannot access methods / properties that require the current class to be instanciated.
您不能在静态方法中使用“$this”。不过，您确实可以访问“self::”，但请记住，您无法访问需要实例化当前类的方法/属性。
回答by Sagar Rabadiya
you have to create new instance and then can access its property
您必须创建新实例，然后才能访问其属性
public static function PayExecute() {
$paymentId = Input::get('paymentId');
$PayerID = Input::get('PayerID');
$cont = (new static)->apiContext;
}
