Linux 如何通过python中的shell管道接收参数？

How to receive arguments via shell pipe in python?

提问by Woltan

I would like to do something like this:

我想做这样的事情：

find -name "foo*" | python main.py

and access all the files that were found by the find program. How do I access that in Python?

并访问 find 程序找到的所有文件。我如何在 Python 中访问它？

采纳答案by Andreas Jung

import sys
for line in sys.stdin:
    print line

回答by David Claridge

Use sys.stdin.read() or raw_input()

使用 sys.stdin.read() 或 raw_input()

A pipeline just changes the stdin file descriptor to point to the pipeline that the command on the left is writing to.

管道只是将 stdin 文件描述符更改为指向左侧命令正在写入的管道。

回答by manojlds

I think you can do:

我认为你可以这样做：

import sys
print sys.stdin.readlines() #or what you want

回答by Michael Kent

I believe fileinputmay be what you want.

我相信fileinput可能是你想要的。

回答by user2343996

I Like using $(...) for command-line arguments that are dependent on some other program. I think this would work for your program python main.py $(find -name "foo*"). Found here

我喜欢将 $(...) 用于依赖于其他程序的命令行参数。我认为这对你的程序有用python main.py $(find -name "foo*")。在这里找到