Javascript $.ajax 如果条件
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$.ajax if condition
提问by olo
I failed to write a condition inside of ajax by using the following syntax.
我无法使用以下语法在 ajax 中编写条件。
var num = 1;
$.ajax({
type: "POST",
//condition starts
if (num === 1){
url: url1,
data: data1,
}else{
url: url2,
data: data2,
}
//condition finishes
success: success,
dataType: dataType
});
but this way works.
但这种方式有效。
var num = 1;
if(num === 1){
$.ajax({
type: "POST",
url: url1,
data: data1,
success: success,
dataType: dataType
});
}else{
$.ajax({
type: "POST",
url: url2,
data: data2,
success: success,
dataType: dataType
});
}
the 2nd method is not quite ideal as repeating my code. is my first script in a wrong syntax? Could someone please point out? thanks
第二种方法不是很理想，因为重复我的代码。我的第一个脚本语法错误吗？有人可以指出吗？谢谢
回答by Bergi
is my first script in a wrong syntax?
我的第一个脚本语法错误吗？
Yes, absolutely. You were just inserting if-else-statement parts in the middle of an object literal. You should use something like this:
是的，一点没错。您只是在对象文字中间插入 if-else-statement 部分。你应该使用这样的东西：
var params = {
type: "POST",
success: success,
dataType: dataType
};
if (num == 1) {
params.url = url1;
params.data = data1;
} else {
params.url = url2;
params.data = data2;
}
$.ajax(params);
Or if you want to inline them, you can use the ternary operator:
或者如果你想内联它们，你可以使用三元运算符：
$.ajax({
type: "POST",
url: (num == 1) ? url1 : url2,
data: (num == 1) ? data1 : data2,
success: success,
dataType: dataType
});
(If you don't want to repeat the condition, store its boolean result in a variable)
（如果您不想重复条件，请将其布尔结果存储在变量中）
回答by Evan Trimboli
You could do it like this:
你可以这样做：
var num = 1, url, data;
if (num === 1) {
url = url1;
data = data1;
} else {
url = url2;
data = data2;
}
$.ajax({
type: "POST",
url: url,
data: data,
success: success,
dataType: dataType
});
回答by Plynx
The stuff in the {braces }is an object literal. You can declare it and modify it before you call $.ajax.
在东西{括号}是一个对象字面。您可以在调用之前声明并修改它$.ajax。
var options =
{
type: "POST",
url: url2,
data: data2,
success: success,
dataType: dataType
};
if (num === 1) { options.url = url; options.data = data; }
$.ajax(options);
回答by nneonneo
$.ajaxtakes a regular JavaScript object, so you can fill it in piecewise:
$.ajax接受一个普通的 JavaScript 对象，所以你可以分段填充它：
request = {type: "POST", success: success, dataType: dataType};
if(num == 1) {
request.url = url1;
request.data = data1;
} else {
request.url = url2;
request.data = data2;
}
$.ajax(request);
回答by allenhwkim
Try this way if url and data are very simple.
如果 url 和 data 非常简单，请尝试这种方式。
var num = 1;
$.ajax({
type: "POST",
url : (num==1? url1 : url2),
data: (num==1? data1 : data2),
success: success,
dataType: dataType
});
回答by Yogu
Place the condition before the ajax statements and assign common variables there.
将条件放在 ajax 语句之前并在那里分配公共变量。
回答by Sahil Grover
Try this:
尝试这个：
var num = 1;
$.ajax({
type: "POST",
url: (num === 1 ? url1 : url2)
data: (num === 1 ? data1 : data2)
success: success,
dataType: dataType
});
But as others have mentioned it would be best to just assign variables outside of the ajax call.
但正如其他人所提到的，最好只在 ajax 调用之外分配变量。
