C# 如何将 Byte[] 转换为 BitmapImage
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How to convert Byte[] to BitmapImage
提问by fma3
I need help, I have this method to get a BitmapImage from a Byte[]
我需要帮助,我有这个方法可以从 Byte[] 获取 BitmapImage
public BitmapSource ByteToBitmapSource(byte[] image)
{
BitmapImage imageSource = new BitmapImage();
using (MemoryStream stream = new MemoryStream(image))
{
stream.Seek(0, SeekOrigin.Begin);
imageSource.BeginInit();
imageSource.StreamSource = stream;
imageSource.CacheOption = BitmapCacheOption.OnLoad;
imageSource.EndInit();
}
return imageSource;
}
imageSource.EndInit();throws an error "We found no imaging component suitable to complete this operation."
imageSource.EndInit();抛出错误“我们发现没有适合完成此操作的成像组件。”
回答by Shimmy Weitzhandler
You should provide us with more info on your image.
I can assume it's unsupported by the system, which I would then advice you to use an external tool, such as imageMagikor any other converter specific to your image.
您应该向我们提供有关您的图像的更多信息。
我可以假设系统不支持它,然后我会建议您使用外部工具,例如imageMagik或任何其他特定于您的图像的转换器。
回答by mlemay
I've made something similar, but it's not with BitmapImage, hopes it can help...
我做了类似的东西,但它不是用 BitmapImage,希望它可以帮助...
First, I get the image from a path, so I get a BMP and cast into a byte[]:
首先,我从路径获取图像,因此我获取 BMP 并转换为字节 []:
private byte[] LoadImage(string szPathname)
{
try
{
Bitmap image = new Bitmap(szPathname, true);
MemoryStream ms = new MemoryStream();
image.Save(ms, ImageFormat.Bmp);
return ms.ToArray();
}catch (Exception){...}
return null;
}
I call this in my code like this:
我在我的代码中这样称呼它:
byte[] bitmapData1 = LoadImage(@"C:\Users\toto\Desktop\test1.bmp");
And when I want to cast the byte[] into System.Windows.Controls.Image I do this:
当我想将 byte[] 转换为 System.Windows.Controls.Image 时,我会这样做:
protected virtual void OnByteArrayChanged(DependencyPropertyChangedEventArgs e)
{
try
{
// PropertyChanged method
BitmapImage bmpi = new BitmapImage();
bmpi.BeginInit();
bmpi.StreamSource = new MemoryStream(ByteArray);
bmpi.EndInit();
System.Windows.Controls.Image image1 = (get my image in my xaml);
image1.Source = bmpi;
}catch (Exception){...}
}
回答by patrick
Set Image.Sourceto a byte array property in XAML.
Image.Source在 XAML 中设置为字节数组属性。
<Image x:Name="MyImage" Source="{Binding Path=MyByteArrayProperty}" />
If you reallywant you can do it in code behind like this
如果你真的想要,你可以像这样在后面的代码中做到这一点
public void DecodePhoto(byte[] byteVal)
{
MemoryStream strmImg = new MemoryStream(byteVal);
BitmapImage myBitmapImage = new BitmapImage();
myBitmapImage.BeginInit();
myBitmapImage.StreamSource = strmImg;
myBitmapImage.DecodePixelWidth = 200;
myBitmapImage.EndInit();
MyImage.Source = myBitmapImage;
}
回答by morishuz
This might also help:
这也可能有帮助:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using System.Drawing;
using System.Runtime.InteropServices;
using System.IO;
using System.ComponentModel;
public class MakeBitmapSource
{
[DllImport("kernel32.dll", EntryPoint = "RtlMoveMemory")]
public static extern void CopyMemory(IntPtr Destination, IntPtr Source, uint Length);
public static BitmapSource FromNativePointer(IntPtr pData, int w, int h, int ch)
{
PixelFormat format = PixelFormats.Default;
if (ch == 1) format = PixelFormats.Gray8; //grey scale image 0-255
if (ch == 3) format = PixelFormats.Bgr24; //RGB
if (ch == 4) format = PixelFormats.Bgr32; //RGB + alpha
WriteableBitmap wbm = new WriteableBitmap(w, h, 96, 96, format, null);
CopyMemory(wbm.BackBuffer, pData, (uint)(w * h * ch));
wbm.Lock();
wbm.AddDirtyRect(new Int32Rect(0, 0, wbm.PixelWidth, wbm.PixelHeight));
wbm.Unlock();
return wbm;
}
public static BitmapSource FromArray(byte[] data, int w, int h, int ch)
{
PixelFormat format = PixelFormats.Default;
if (ch == 1) format = PixelFormats.Gray8; //grey scale image 0-255
if (ch == 3) format = PixelFormats.Bgr24; //RGB
if (ch == 4) format = PixelFormats.Bgr32; //RGB + alpha
WriteableBitmap wbm = new WriteableBitmap(w, h, 96, 96, format, null);
wbm.WritePixels(new Int32Rect(0, 0, w, h), data, ch * w, 0);
return wbm;
}
}

