Java - 只对数组的子部分进行排序
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Java - sort only subsection of array
提问by SoluableNonagon
I have an array of characters
我有一个字符数组
String a = "badabcde";
char[] chArr = a.toCharArray(); // 'b','a','d','a','b','c','d','e'
What's the easiest way to sort only a section of the array, given a start and end index?
给定开始和结束索引，仅对数组的一部分进行排序的最简单方法是什么？
// 'b','a','d','a','b','c','d','e'
subSort(array, startIndex, endIndex);
Ex:
subSort(chArr, 2, 5);
// 'b','a','a','b','c','d','d','e' // sorts indices 2 to 5
回答by emin
I think public static void sort(char[] a, int fromIndex, int toIndex)answers your question.
我认为public static void sort(char[] a, int fromIndex, int toIndex)回答了你的问题。
String a = "badabcde";
char[] chArr = a.toCharArray(); // 'b','a','d','a','b','c','d','e'
// fromIndex - the index of the first element (inclusive) to be sorted
// toIndex - the index of the last element (exclusive) to be sorted
Arrays.sort(chArr,2,6);
回答by Eran
Use public static void sort(char[] a, int fromIndex, int toIndex)in Arraysclass.
使用公共静态无效的排序（的char []一，INT的fromIndex，INT toIndex）的Arrays类。
In your example:
在你的例子中：
Arrays.sort(chArr,2,6); // note that fromIndex is inclusive
// but toIndex is exclusive
回答by hoat4
Use Arrays.sort([], int startIndex, int endIndex).
使用Arrays.sort([], int startIndex, int endIndex)。
String a = "badabcde";
char[] chArr = a.toCharArray(); // 'b','a','d','a','b','c','d','e'
Arrays.sort(chArr, 2, 5);
System.out.println(new String(chArr)); // this prints baabdcde
