Java WebDriver 查找不包含属性的元素
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WebDriver find Element not containing attribute
提问by aeinstein83
I have following HTML
我有以下 HTML
<button class="x-btn-text " style="position: relative; width: 69px;" type="button" tabindex="0" aria-disabled="false">OK</button>
<button class="x-btn-text" style="position: relative; width: 69px;" type="button" tabindex="0">OK</button>
The first button is disabled and the second button is enabled, since I want to click on the enabled button. Is there a way I could find the element, that doesn't have attribute aria-disabled?
第一个按钮被禁用，第二个按钮被启用，因为我想点击启用的按钮。有没有办法找到没有属性的元素aria-disabled？
采纳答案by Yi Zeng
ExtJs case. Here you need determine if it's enabled or not by attribute aria-disabled="false"using getAttribute("aria-disabled")or XPath/CssSelector.
ExtJs 案例。在这里，您需要通过属性aria-disabled="false"usinggetAttribute("aria-disabled")或 XPath/CssSelector确定它是否已启用。
So Code Enthusiastic's logic should be correct, however ExtJS is always special on something.
所以Code Enthusiastic 的逻辑应该是正确的，但是ExtJS 在某些方面总是很特别。
List<WebElement> okButtons = driver.findElements(By.xpath("//button[text() = 'OK']"));
for (WebElement okButton : okButtons) {
if (!okButton.getAttribute("aria-disabled").equals("false")) {
okButton.click();
break;
}
}
Or even easier, rule out the enabled one in your locator. (As you need to text here, so no suitable locator using CssSelector, only XPath)
或者更简单的是，排除定位器中启用的那个。（由于您需要在此处输入文本，因此没有合适的定位器使用 CssSelector，只有 XPath）
WebElement enabledokButton = driver.findElement(By.xpath("//button[text() = 'OK' and not(@aria-disabled = 'false')]"));
enabledokButton.click();
回答by Code Enthusiastic
List<WebElement> okButtons = driver.findElements(By.xpath("//button[text() = 'OK']"));
for (WebElement okButton : okButtons) {
if (okButton.isEnabled()) {
okButton.click();
break;
}
}
回答by ddavison
Is there a way I could find the element, that doesn't have attribute aria-disabled?
有没有办法找到没有 aria-disabled 属性的元素？
YES! Utilize CSS!
是的！使用CSS！
Your selector to find a button without the aria-disabledattribute would be, button:not([aria-disabled])
您查找没有该aria-disabled属性的按钮的选择器将是，button:not([aria-disabled])
driver.findElement(By.cssSelector("button:not([aria-disabled])").click();
