Javascript 如何使用javascript替换字符串中最后一次出现的字符
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How to replace last occurrence of characters in a string using javascript
提问by Henrik Stenb?k
I'm having a problem finding out how to replace the last ', ' in a string with ' and ':
我在找出如何用 ' 和 ' 替换字符串中的最后一个 ', ' 时遇到问题：
Having this string: test1, test2, test3
有这个字符串：test1、test2、test3
and I want to end out with: test1, test2 and test3
我想以：test1、test2 和 test3 结束
I'm trying something like this:
我正在尝试这样的事情：
var dialog = 'test1, test2, test3';
dialog = dialog.replace(new RegExp(', /g').lastIndex, ' and ');
but it's not working
但它不起作用
回答by annakata
foo.replace(/,([^,]*)$/, ' and ')
use the $(end of line) anchor to give you your position, and look for a pattern to the right of the comma index which does not include any further commas.
使用$（行尾）锚点为您提供位置，并在逗号索引右侧查找不包含任何其他逗号的模式。
Edit:
编辑：
The above works exactly for the requirements defined (though the replacement string is arbitrarily loose) but based on criticism from comments the below better reflects the spirit of the original requirement.
以上完全适用于定义的要求（尽管替换字符串随意松散）但基于评论的批评，以下更好地反映了原始要求的精神。
console.log(
'test1, test2, test3'.replace(/,\s([^,]+)$/, ' and ')
)回答by splash
result = dialog.replace(/,\s(\w+)$/, " and ");
$1is referring to the first capturing group (\w+)of the match.
$1指(\w+)的是比赛的第一个捕获组。
回答by ricksalmon
regex search pattern \s([^,]+)$
正则表达式搜索模式 \s([^,]+)$
Line1: If not, sdsdsdsdsa sas ., sad, whaterver4
Line2: If not, fs sadXD sad , ,sadXYZ!X
Line3: If not d,,sds,, sasa sd a, sds, 23233
Search with patterns finds Line1: whaterver4 Line3: 23233
使用模式搜索找到 Line1：whaterver4 Line3：23233
Yet doesnt find Line2: sadXYZ!X
Which is only missing a whitespace
然而没有找到 Line2: sadXYZ!X
只缺少一个空格
