在执行 JPA 查询时获取 NoSuchMethodError:javax.persistence.Table.indexes()

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时间:2020-08-13 15:39:51  来源:igfitidea点击:

Getting NoSuchMethodError: javax.persistence.Table.indexes() while performing JPA query

javahibernatepostgresqljpaintellij-idea

提问by J.Olufsen

I have IntelliJ project with libraries: Hibernate-entitymanager 4.3.4 and JPA 2.0-2.0. Which is connected to database using postgresql-9.3.1100.jdbc4. How to fix it?

我有带库的 IntelliJ 项目:Hibernate-entitymanager 4.3.4 和 JPA 2.0-2.0。使用 postgresql-9.3.1100.jdbc4 连接到数据库。如何解决?

jpa-ql> select ItemEntity.name from ItemEntity;

jpa-ql> 从 ItemEntity 中选择 ItemEntity.name;

java.lang.NoSuchMethodError: javax.persistence.Table.indexes()[Ljavax/persistence/Index;
    at org.hibernate.cfg.annotations.EntityBinder.processComplementaryTableDefinitions(EntityBinder.java:936)
    at org.hibernate.cfg.AnnotationBinder.bindClass(AnnotationBinder.java:824)
    at org.hibernate.cfg.Configuration$MetadataSourceQueue.processAnnotatedClassesQueue(Configuration.java:3790)
    at org.hibernate.cfg.Configuration$MetadataSourceQueue.processMetadata(Configuration.java:3744)
    at org.hibernate.cfg.Configuration.secondPassCompile(Configuration.java:1410)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1844)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.perform(EntityManagerFactoryBuilderImpl.java:850)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.perform(EntityManagerFactoryBuilderImpl.java:843)
    at org.hibernate.boot.registry.classloading.internal.ClassLoaderServiceImpl.withTccl(ClassLoaderServiceImpl.java:397)
    at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:842)
    at org.hibernate.jpa.HibernatePersistenceProvider.createEntityManagerFactory(HibernatePersistenceProvider.java:73)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:78)
    at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54)
    at com.intellij.jpa.remote.impl.JpaFacadeImpl.createEntityManagerFactory(JpaFacadeImpl.java:16)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at sun.rmi.server.UnicastServerRef.dispatch(UnicastServerRef.java:322)
    at sun.rmi.transport.Transport.run(Transport.java:177)
    at sun.rmi.transport.Transport.run(Transport.java:174)
    at java.security.AccessController.doPrivileged(Native Method)
    at sun.rmi.transport.Transport.serviceCall(Transport.java:173)
    at sun.rmi.transport.tcp.TCPTransport.handleMessages(TCPTransport.java:556)
    at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run0(TCPTransport.java:811)
    at sun.rmi.transport.tcp.TCPTransport$ConnectionHandler.run(TCPTransport.java:670)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
    at java.lang.Thread.run(Thread.java:744)

采纳答案by SJuan76

Just read the documentation:

只需阅读文档:

http://docs.oracle.com/javaee/7/api/javax/persistence/Table.html#indexes()

http://docs.oracle.com/javaee/7/api/javax/persistence/Table.html#indexes()

Specifically, the lines

具体来说,线条

Since:Java Persistence 2.1

从:Java 持久性 2.1