Java - 如何在数组中找到字符串的长度？
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Java - How do I find the length of a string in an array?
提问by Zach Fortney
All I need to know is how to find the length of the string inside of the array. I also would like to know how to find which string comes first in alphabetical order in the array.
我只需要知道如何在数组中找到字符串的长度。我还想知道如何在数组中按字母顺序查找哪个字符串排在第一位。
回答by Alex Vulaj
myArr[0].length()
myArr[0].length()
This will access the string at location 0, then get the length of it.
这将访问位置 0 处的字符串，然后获取它的长度。
Also, for sorting alphabetically, you can use
此外，要按字母顺序排序，您可以使用
Arrays.sort(myArr);
Arrays.sort(myArr);
回答by Mohammad Adil
You can simply use .lengthmethod on any string array element to get its length,
And to sort that array alphabetically you ca use .sortmethod -
您可以简单地.length在任何字符串数组元素上使用方法来获取其长度，并按字母顺序对该数组进行排序，您可以使用.sort方法 -
For example -
例如 -
String[] strings = { "Hello ", "This ", "is", "Sorting", "Example" };
Arrays.sort(strings);
So after sorting strings[0]would be Exampleand string[0].length()would be 7
所以在排序之后strings[0]将会是Example并且string[0].length()将会是7
