python 从python列表中获取第一个非空字符串
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Get first non-empty string from a list in python
提问by Simon D
In Python I have a list of strings, some of which may be the empty string. What's the best way to get the first non-empty string?
在 Python 中，我有一个字符串列表，其中一些可能是空字符串。获得第一个非空字符串的最佳方法是什么？
回答by Wojciech Bederski
next(s for s in list_of_string if s)
Edit: py3k proof version as advised by Stephan202 in comments, thanks.
编辑：按照 Stephan202 在评论中的建议，py3k 证明版本，谢谢。
回答by sykora
To remove all empty strings,
要删除所有空字符串，
[s for s in list_of_strings if s]
[s for s in list_of_strings if s]
To get the first non-empty string, simply create this list and get the first element, or use the lazy method as suggested by wuub.
要获取第一个非空字符串，只需创建此列表并获取第一个元素，或者使用 wuub 建议的惰性方法。
回答by SilentGhost
def get_nonempty(list_of_strings):
for s in list_of_strings:
if s:
return s
回答by Steve Losh
Here's a short way:
这是一个简短的方法：
filter(None, list_of_strings)[0]
EDIT:
编辑：
Here's a slightly longer way that is better:
这是一个稍微长一点的更好的方法：
from itertools import ifilter
ifilter(None, list_of_strings).next()
回答by Steve Losh
Based on your question I'll have to assume a lot, but to "get" the first non-empty string:
根据您的问题，我必须假设很多，但要“获取”第一个非空字符串：
(i for i, s in enumerate(x) if s).next()
which returns its index in the list. The 'x' binding points to your list of strings.
它返回它在列表中的索引。'x' 绑定指向您的字符串列表。
回答by ghostdog74
to get the first non empty string in a list, you just have to loop over it and check if its not empty. that's all there is to it.
要获取列表中的第一个非空字符串，您只需遍历它并检查它是否不为空。这里的所有都是它的。
arr = ['','',2,"one"]
for i in arr:
if i:
print i
break
