C# 正则表达式获取第一个空格后的所有内容
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Regex to get everything after the first space
提问by torres
What would the syntax to get all the words in a string after the first space. For example, bobs nice house. So the result should be " nice house" without the quote.
在第一个空格之后获取字符串中所有单词的语法是什么。例如，鲍勃漂亮的房子。所以结果应该是没有引用的“漂亮的房子”。
([^\s]+)gives me all 3 words seperated by ;
([^\s]+)给我所有由 ; 分隔的 3 个词
,[\s\S]*$ >not compiling.
,[\s\S]*$ >不编译。
回答by MarcinJuraszek
I think it should be done this way:
我认为应该这样做：
[^ ]* (.*)
It allows 0 or more elements that are not a space, than a single space and selects whatever comes after that space.
它允许 0 个或多个不是空格的元素，而不是单个空格，并选择该空格之后的任何元素。
C# usage
C# 用法
var input = "bobs nice house";
var afterSpace = Regex.Match(input, "[^ ]* (.*)").Groups[1].Value;
afterSpaceis "nice house".
afterSpace是"nice house"。
To get that first space as well in result string change expression to [^ ]*( .*)
要在结果字符串中也获得第一个空格，请将表达式更改为 [^ ]*( .*)
No regex solution
没有正则表达式解决方案
var afterSpace = input.Substring(input.IndexOf(' '));
回答by Soner G?nül
Actually, you don't need to use regex for that process. You just need to use String.Split()method like this;
实际上，您不需要在该过程中使用正则表达式。你只需要使用这样的String.Split()方法；
string s = "bobs nice house";
string[] s1 = s.Split(' ');
for(int i = 1; i < s1.Length; i++)
Console.WriteLine(s1[i]);
Output will be;
输出将是；
nice
house
Here is a DEMO.
这是一个DEMO.
回答by torres
I was really looking shortest possible code. following did the job. thanks guys
我真的在寻找最短的代码。以下做了这项工作。谢谢你们
\s(.*)
