BASH - 在 shell 脚本上获取 UID 不起作用
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BASH - getting UID on shell script does not work
提问by Eric Lee
Hi I have a question about bash.
嗨，我有一个关于 bash 的问题。
and I'm new to it.
我是新手。
I made a file named "test.sh" and its contents is
我制作了一个名为“test.sh”的文件，其内容是
#!/bin/bash
set -x
echo $UID
echo "$UID"
echo "$(id -u)"
and the result is blank!! nothing shows up
结果是空白！！什么都没有出现
However, when i just type "echo $UID" on terminal it shows "1011"
但是，当我在终端上输入“echo $UID”时，它显示“1011”
is there anything i missed for bash?
有什么我错过的 bash 吗？
Please help
请帮忙
UPDATED
更新
bash version is 4.3.11 and I typed "sh test.sh" to execute.
bash 版本是 4.3.11，我输入了“sh test.sh”来执行。
and the result is
结果是
+ echo
+ echo
+ id -u
+ echo 1011
1011
thanks!
谢谢！
采纳答案by SLePort
$UIDis a Bash variable that is not set under sh, that may be why it outputs blank lines.
$UID是一个未在 下设置的 Bash 变量sh，这可能就是它输出空行的原因。
Try bash test.shor make your script executable with chmod u+x test.sh, the program defined in shebang will then be used (/bin/bash)
尝试bash test.sh或使您的脚本可执行chmod u+x test.sh，然后将使用在 shebang 中定义的程序 ( /bin/bash)
